Question

What is the pressure on a horizontal surface with an area of 8 msquared that is 4 m​ underwater? Use 1000 kg divided by m cubed for the density of water and 9.8 m divided by s squared for the acceleration due to gravity. What is the correct relationship to use to find the pressure on the horizontal​ surface?

Answer 1

Answer:

140525 pa

Explanation:

$h$ = depth of water = 4 m

$A$ = Area of surface = 8 m²

$\rho$ = Density of water = 1000 kg m⁻³

tex]g[/tex] = acceleration due to gravity = 9.8 ms⁻²

$P_{o}$ = Atmospheric pressure = 101325 Pa

$P$ = Pressure at the given depth "h"

Pressure at the given depth is given as

$P = P_{o} + \rho g h\\P = 101325 + (1000) (9.8) (4)\\P = 140525 pa$