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grin007 [14]
3 years ago
7

What is the pressure on a horizontal surface with an area of 8 msquared that is 4 m​ underwater? Use 1000 kg divided by m cubed

for the density of water and 9.8 m divided by s squared for the acceleration due to gravity. What is the correct relationship to use to find the pressure on the horizontal​ surface?
Physics
1 answer:
LUCKY_DIMON [66]3 years ago
7 0

Answer:

140525 pa

Explanation:

h = depth of water = 4 m

A = Area of surface = 8 m²

\rho = Density of water = 1000 kg m⁻³

tex]g[/tex] = acceleration due to gravity = 9.8 ms⁻²

P_{o} = Atmospheric pressure = 101325 Pa

P = Pressure at the given depth "h"

Pressure at the given depth is given as

P = P_{o} + \rho g h\\P = 101325 + (1000) (9.8) (4)\\P = 140525 pa

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