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grin007 [14]
3 years ago
7

What is the pressure on a horizontal surface with an area of 8 msquared that is 4 m​ underwater? Use 1000 kg divided by m cubed

for the density of water and 9.8 m divided by s squared for the acceleration due to gravity. What is the correct relationship to use to find the pressure on the horizontal​ surface?
Physics
1 answer:
LUCKY_DIMON [66]3 years ago
7 0

Answer:

140525 pa

Explanation:

h = depth of water = 4 m

A = Area of surface = 8 m²

\rho = Density of water = 1000 kg m⁻³

tex]g[/tex] = acceleration due to gravity = 9.8 ms⁻²

P_{o} = Atmospheric pressure = 101325 Pa

P = Pressure at the given depth "h"

Pressure at the given depth is given as

P = P_{o} + \rho g h\\P = 101325 + (1000) (9.8) (4)\\P = 140525 pa

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A spacecraft of mass 1500 kg orbits the earth at an altitude of approximately 450 km above the surface of the earth. Assuming a
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1.28 x 10^4 N

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2 years ago
Consider a Carnot heat-engine cycle executed in a closed system using 0.025 kg of steam as the working fluid. It is known that t
ArbitrLikvidat [17]

Answer:

The temperature of the steam during the heat rejection process is 42.5°C

Explanation:

Given the data in the question;

the maximum temperature T_H in the cycle is twice the minimum absolute temperature T_L in the cycle

T_H  = 0.5T_L

now, we find the efficiency of the Carnot cycle engine

η_{th = 1 - T_L/T_H

η_{th = 1 - T_L/0.5T_L

η_{th = 0.5

the efficiency of the Carnot heat engine can be expressed as;

η_{th = 1 - W_{net/Q_H

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we substitute

0.5 = 60 / Q_H

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T_L = 40 + ( 45 - 40 ) ( \frac{2400-2406.0}{2394.0-2406.0}\\} )

T_L = 40 + (5) × (0.5)

T_L = 40 + 2.5

T_L = 42.5°C  

Therefore, The temperature of the steam during the heat rejection process is 42.5°C  

4 0
3 years ago
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