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grin007 [14]
3 years ago
7

What is the pressure on a horizontal surface with an area of 8 msquared that is 4 m​ underwater? Use 1000 kg divided by m cubed

for the density of water and 9.8 m divided by s squared for the acceleration due to gravity. What is the correct relationship to use to find the pressure on the horizontal​ surface?
Physics
1 answer:
LUCKY_DIMON [66]3 years ago
7 0

Answer:

140525 pa

Explanation:

h = depth of water = 4 m

A = Area of surface = 8 m²

\rho = Density of water = 1000 kg m⁻³

tex]g[/tex] = acceleration due to gravity = 9.8 ms⁻²

P_{o} = Atmospheric pressure = 101325 Pa

P = Pressure at the given depth "h"

Pressure at the given depth is given as

P = P_{o} + \rho g h\\P = 101325 + (1000) (9.8) (4)\\P = 140525 pa

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A filled water tower sits on the top of the highest hill near a city. The cylindrical tower has a height of 55.0 m
Reika [66]

Answer:

539 kPa

Explanation:

Pressure equals density times acceleration of gravity times depth.

P = ρgh

Water has a density of 1000 kg/m³, and acceleration of gravity is 9.8 m/s².

P = (1000 kg/m³) (9.8 m/s²) (55.0 m)

P = 539,000 Pa

P = 539 kPa

7 0
3 years ago
A capacitor with a capacitance of 50µf when connected to a battery of 400 V. The charge and energy stored on it is? a. 0.05 C an
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Answer:

c. 0.02 C and 4 J

Explanation:

Applying,

Q = CV................ Equation 1

Where Q = Charge, C = Capacitance of the capacitor, V = Voltage.

From the question,

Given: C = 50 μF = 50×10⁻⁶ F, V = 400 V

Substitute these values into equation 1

Q = (50×10⁻⁶)(400)

Q = 0.02 C.

Also Applying

E = CV²/2............. Equation 2

Where E = Energy stored.

Therefore,

E = (50×10⁻⁶ )(400²)/2

E = 4 J

Hence the right option is c. 0.02 C and 4 J

3 0
2 years ago
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Answer: False

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Answer:

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Explanation:

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