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ki77a [65]
3 years ago
15

For a beam of light in air (n = 1) reflecting off glass (n = 1.5), what is Brewster's angle to the nearest degree?

Physics
1 answer:
Georgia [21]3 years ago
4 0

Answer: 56°

Explanation:

Brewster's angle refers to the angle at the point where light of a certain polarization passes through a transparent dielectric surface and is transmitted perfectly such that no reflection is made.

The formula is;

= Tan^{-1} (\frac{n_{2} }{n_{1}} )

= Tan^{-1} (\frac{1.5 }{1} )

= 56.30993247

= 56°

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Answer:

Explanation:

Use the one-dimensional equation

Δx = v_0t+\frac{1}{2}at^2 where delta x is the displacement of the object, v0 is the velocity of the object, a is the pull of gravity, and t is the time in seconds. That's our unknown.

Δx = -2 (negative because where it ends up is lower than the point at which it started),

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a = -9.8

Filling in:

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-2=5t-4.9 t^2

this should look hauntingly familiar (a quadratic, which is parabolic motion...very important in physics!!). We begin by getting everything on one side of the equals sign and solving for t by factoring:

-4.9 t^2+5t+2=0 (the 0 is also indicative of the object landing on the ground! Isn't this a beautiful thing, how it all just works so perfectly together?)

When you factor this however your math/physics teacher has you factoring you will get that

t = 1.3 sec and t = -.31 sec

Since we all know that time can NEVER be negative, it takes the ball 1.3 sec to hit the ground from a height of 2 m if it is rolling off the shelf at 5 m/s.

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K-2/5=11k literal equations
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