Help me fill this page with the right answer please (17 lines minimum please)
2 answers:
Hey Lenny lately I’ve been having a rough time in the water cycle. It all started when I was chilling in my favorite location the “glaciars” and suddenly the sun turned me into liquid form. Next thing I know I am hurdling down a river straight into a massive lake. Personally this is my least favorite stage of the water cycle because of kids and bacteria that lurk in the water, very scary things. I didn’t stop at the lake very long, and instead sunk into the soil in a process called collection so I could become ground water. Underground reservoir’s are much more peaceful then lakes and I wanted to stay there. However I was forced up a water well pump shortly after and sent through a long tube. Me and couple of the friends I met on the way were all dispersed over a giant grass feild. Many molecules in the group were captured by the hostile plants but I escaped through the means of evaporation. Currently I have condensed into cloud form and I am roaming the skies looking for you, when you get this let me know and I’ll percipitate in your area! P.s I found this photo of us freezing over in the ice age lollll.
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The reaction is of order three with respect to the reactant.
<h3>Explanation</h3>The rate of a reaction of order n about a certain reactant is proportion to the concentration of that reactant raised to the n-th power. This is true only if concentrations of any other reactants stay constant in the whole process.
In other words, Rate = constant × [Reactant]ⁿ, Rate ∝ [Reactant]ⁿ. (The symbol "∝" reads "proportional to".)
In this question,
[4 × Reactant]ⁿ ÷ [Reactant]ⁿ = 64.
In other words, 4ⁿ = 64, where n is the order of the reaction with respect to this reactant.
It might take some guesswork to find the value of n. Alternatively, n can be solved directly with a calculator using logarithms. Taking natural log of both sides:
.
Evaluating on Google or on a calculator with support for ln (the natural log) will give the value of n- no guesswork required.
n = 3. Therefore, the reaction is of order three with respect to this reactant.
Answer:
Are produced 12,1 g of AlCl₃ and 5,33 g of Al₂O₃ are left over
Explanation:
For the reaction:
Al₂O₃ (s) + 6 HCl (aq) → 2AlCl₃ (aq) + 3H₂0(l)
10,0g of Al₂O₃ are:
10,0g ₓ = <em>0,0980 moles</em>
And 10,0g of HCl are:
10,0 gₓ = <em>0,274 moles</em>
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For a total reaction of 0,274 moles of HCl you need:
0,274× = <em>0,0457 moles of Al₂O₃</em>
Thus, limiting reactant is HCl
The grams produced of AlCl₃ are:
0,274 moles HCl × × 133
= <em>12,1 g of AlCl₃</em>
<em />
The moles of Al₂O₃ that don't react are:
0,0980 moles - 0,0457 moles =<em> </em>0,0523 moles
And its mass is:
0,0523 molesₓ = <em>5,33 g of Al₂O₃ </em>
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I hope it helps!