1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ddd [48]
3 years ago
6

Lightning is an example of

Chemistry
1 answer:
Vikentia [17]3 years ago
6 0

Answer:

yes great job you do know that you can make high voltage capacitors to store static electricity just look up ElectroBooms high voltage capacitor he made it's very useful if you want to learn more.

You might be interested in
You are provided with a compound fertilizer, 40-15-10.Calculate the quantity of fertilizer to add to a one hectare field supply
victus00 [196]

Answer:

a. 300 kg of Fertilizer

b. 225 kg of fertilizer

c.400 Kg of fertilizer

d.600 Kg of fertilizer

Explanation:

The percentage composition ratio of Nitrogen, Phosphorus and Potassium bag of the given fertilizer is 40:15:10.

The percentages can be expressed as fractions as follows:

For nitrogen; 40/100 = 0.4

For phosphorus; 15/100 = 0.15

For potassium; 10/100 = 0.1

To find the quantity of fertilizer required to add to a hectare to supply the given amount of nutrients, the amount to be provided is divided by the percentage or fractional compostion of each nutrient.

Quantity of fertilizer required to add to a hectare to supply;

a. Nitrogen at 120 kg/ha = 120/0.4 = 300 Kg of fertilizer

b.. Nitrogen at 90 Kg/ha = 90/0.4 = 225 Kg of fertilizer

c. Phosphorus at  60 kg/ha = 60/0.15 = 400 Kg of fertilizer

d. Potassium at 60 kg/ha = 60/0.1 = 600 Kg of fertilizer

5 0
3 years ago
What instrument is used to measure heat released or absorbed in a reaction?
kirill115 [55]

Answer:

A calorimeter is used.

:

6 0
3 years ago
What is the percent yield of ferrous sulfide if the actual yield is 220.0 g and the theoretical yield is 275.6 g
Anika [276]
To get the percent yield, we will use this formula: ((Actual Yield)/(Theoretical Yield)) * 100% Values given: actual yield is 220.0 g theoretical yield is 275.6 g Now, let us substitute the values given. (220.0 grams)/(275.6 grams) = 0.7983 Then, to get the percentage, multiply the quotient by 100. 0.7983 (100) = 79.83% Among the choices, the most plausible answer is 79.8% <span>
</span>
4 0
3 years ago
Read 2 more answers
The blue color of the sky results from the scattering of sunlight by air molecules. The blue light has a frequency of about 7.5
vazorg [7]

A) c = 3 x 10^8 m/s 
f = 7.15 x 10^14 Hz 
c = λ x f (=) λ = 3 x 10^8 / 7.15 x 10^14 = 4.19 x 10^-7 m = 419.6 nm 

B) E = h  f 
H = Planck's constant = 6.63 x 10^-34 J/s 
E = 6.63 x 10^-34 x 7.15 x 10^14 = 4.74 x 10^-19 J

Read more on Brainly.com - brainly.com/question/5760368#readmore
3 0
3 years ago
How strongly gravity pulls on an objects mass is the object
Lemur [1.5K]
Yes ...................................
5 0
3 years ago
Other questions:
  • 6) Sodium bicarbonate can be further broken down into simpler substances by chemical means only. Therefore, sodium bicarbonate i
    6·2 answers
  • What part of a cell regulates the movement of materials in and out of the cell
    15·2 answers
  • How many moles of hydrogen will be produced in this reaction when 34.5 moles of hydrogen iodide are decomposed?
    11·1 answer
  • 10. If 200. L of ammonia (NH3) are produced in the reaction between nitrogen and hydrogen at STP, how many
    8·1 answer
  • Select the correct answer.
    13·2 answers
  • What volume of 18.0 M H2SO4 is needed to contain 2.45 moles of H2SO4?
    9·1 answer
  • These are the photos for part A
    12·1 answer
  • (reposted) thank you :)))
    12·1 answer
  • Question 5 (1 point)<br> How many moles of oxygen gas is needed to produce 36 grams of water?
    7·1 answer
  • Give below are the four mixtures. Choose the correct one which can be separated by winnowing. (i) soybean and chickpeas (ii) whe
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!