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Ipatiy [6.2K]
2 years ago
13

A 0.250 kg block attached to a light spring oscillates on a frictionless, horizontal table. The oscillation amplitude is A = 0.1

25 m and the block moves at 3.00 m/s as it passes through equilibrium at x = 0. (a) Find the spring constant, k.
Physics
1 answer:
bulgar [2K]2 years ago
8 0

The spring constant, k will be 18 N/m.The ratio of force to one unit of displaced length is known as the spring constant.

<h3>What is the spring constant?</h3>

Spring constant is defined as the ratio of force per unit displaced length.

Given data;

Mass of  block,m=0.250 k

Amplitude,A = 0.125 m

Velocity,V=3.00 m/

Spring constant,K=?

The formula for the spring constant when the spring is oscillate at the given amplitude A:

\rm K = \frac{V_{max}^2 m}{A} \\\\  K = \frac{3.0 \times 0.250}{0.125} \\\\ K=18 \ N/m

Hence, the spring constant, k will be 18 N/m

To learn more about the spring constant, refer:

brainly.com/question/4291098

#SPJ1

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5) Due to the conservation of energy / due to the presence of friction

6) The work done is 4000 J

7) The distance travelled by the object is 4 m

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Explanation:

5)

For a roller coaster in motion along the track, in absence of friction, the mechanical energy remains constant:

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6)

The work done when lifting an object is equal to the gravitational potential energy gained by the object:

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7)

The work done when pushing an object in a direction parallel to the motion of the object is given by:

W=Fd

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F is the magnitude of the force

d is the distance through which the object has travelled through

In this problem, we have:

W = 300 J (work done)

F = 75 N (magnitude of the force)

Solving the equation for d, we find the distance travelled:

d=\frac{W}{F}=\frac{300}{75}=4 m

8)

The potential energy of an object is the energy possessed by an object due to its position in a gravitational field. Near the Earth's surface, it is given by

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h = 50 m (height)

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Learn more about potential energy:

brainly.com/question/1198647

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