Landing with a speed of 81.9 m/s, and traveling due south, a jet comes to rest in 949m. Assuming the jet slows with constant acc
eleration, find the magnitude and direction of its acceleration.
1 answer:
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The force on a charged particle on a magnetic field is given by:
where B is the magnitude of the field, q is the charge of the particle, v is its velocity and θ is the angle between the field and the velocity of the particle.
In this case we have that:
• The magnitude of the field is 0.09 T.
,• The charge of the particle is 3.2 x 10 –19C .
,• The velocity is 3.0 × 10 4 m/s
,• The angle between the field and the velocity is 90°, since they are perpendicular.
Plugging these we have:
Therefore, the force on the charge is: