(y + 1)^3 would just be dividing the two
If you want it completely simplified, then it’s the following:
(y + 1)(y + 1)(y + 1)
= y^2 + y + y + 1 (y + 1)
= y^2 + 2y + 1 (y + 1)
= y^3 + y^2 + 2y^2 + 2y + y + 1
= y^3 + 3y^2 + 3y + 1
Answer:
Step-by-step explanation:
okay, so here are a few methods you can use.
___
1) +
x + 7 = 10 so because this is addition we use the reverse, subtraction. So
x - 7 = 10 - 7 and that equals to 3.
2) -
x - 2 = 10 so because this is subtraction we do the reverse, addition.
x + 2 = 10 + 2 and that equals to 12.
3) x
x times 3 = 21 because this is multiplying we divide.
x/3 = 21/3 and that would be 7.
4) /
x/2 = 10 same as above, reverse is multiplying.
x times 2 = 10 times 2 and thats 20.
GL!
The answer is the first and the third figure,attached
Answer:
The Sum Of The Integers From -6 To 58 is <u>1690.</u>
Step-by-step explanation:
Given,


We have to find out the sum of integers from -6 To 58.
Firstly we will find out the total number of terms that is 'n'.
Here 

Now we use the formula of A.P.

On substituting the values, we get;

So there are 65 terms in between -6 To 58.
That means we have to find the sum of 65 terms in between -6 To 58.
Now we use the formula of Sum of n_terms.

On substituting the values, we get;

Hence The Sum Of The Integers From -6 To 58 is <u>1690.</u>
Answer:
203.5
Step-by-step explanation:
Please mark brainliest.