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nataly862011 [7]

2 years ago

14

Ms. Lui earned an annual income of 775,000, what is the weekly salary?

1 answer:

jok3333 [9.3K]2 years ago

4 0

Answer:

$14,903.85

Step-by-step explanation:

So, Ms. Lui earns $775,000 each year. To find the weekly salary, we have to divide the annual income by the amount of weeks in a year. There are about 52 weeks in one year. Let's find the weekly salary:

$\frac{775000}{52} = 14,903.85$

Therefore, Ms. Lui earns $14,903.85 a week.

Hope this helps! If you have questions about my work, please leave them in the comments!

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Can i have help please

IgorLugansk [536]

(y + 1)^3 would just be dividing the two

If you want it completely simplified, then it’s the following:

(y + 1)(y + 1)(y + 1)

= y^2 + y + y + 1 (y + 1)

= y^2 + 2y + 1 (y + 1)

= y^3 + y^2 + 2y^2 + 2y + y + 1

= y^3 + 3y^2 + 3y + 1

7 0

2 years ago

I need help FAST!!!!

Pavel [41]

Answer:

Step-by-step explanation:

okay, so here are a few methods you can use.

___

1) +

x + 7 = 10 so because this is addition we use the reverse, subtraction. So

x - 7 = 10 - 7 and that equals to 3.

2) -

x - 2 = 10 so because this is subtraction we do the reverse, addition.

x + 2 = 10 + 2 and that equals to 12.

3) x

x times 3 = 21 because this is multiplying we divide.

x/3 = 21/3 and that would be 7.

4) /

x/2 = 10 same as above, reverse is multiplying.

x times 2 = 10 times 2 and thats 20.

GL!

6 0

3 years ago

Which of these triangle pairs can be mapped to each other using a translation and a rotation about a point A? Select one answer

Elenna [48]

The answer is the first and the third figure,attached

5 0

2 years ago

Question: Find The Sum Of The Integers From -6 To 58 Of Ss. O 1,500 O 1,734 O 1,690 O 1,621

REY [17]

Answer:

The Sum Of The Integers From -6 To 58 is <u>1690.</u>

Step-by-step explanation:

Given,

$a=-6$

$T_n=58$

We have to find out the sum of integers from -6 To 58.

Firstly we will find out the total number of terms that is 'n'.

Here $a_1=-6\ and\ a_2=-5$

$\therefore d=a_2-a_1=-5-(-6)=-5+6=1$

Now we use the formula of A.P.

$T_n=a+(n-1)d$

On substituting the values, we get;

$58=-6+(n-1)1\\\\n-1=58+6\\\\n-1=64\\\\n=64+1=65$

So there are 65 terms in between -6 To 58.

That means we have to find the sum of 65 terms in between -6 To 58.

Now we use the formula of Sum of n_terms.

$S_n=\frac{n}{2}(2a-(n-1)d)$

On substituting the values, we get;

$S_{65}=\frac{65}{2}(2\times-6+(65-1)1)\\\\S_{65}=\frac{65}{2}(-12+64)\\\\S_{65}=\frac{65}{2}\times52\\\\S_{65}=65\times26=1690$

Hence The Sum Of The Integers From -6 To 58 is <u>1690.</u>

5 0

3 years ago

Estimate the quotient: 1628 ÷ 8

Pachacha [2.7K]

Answer:

203.5

Step-by-step explanation:

Please mark brainliest.

4 0

2 years ago

Read 2 more answers