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Nutka1998 [239]
3 years ago
14

Cody has $700 in a savings account that pays 4% simple interest. How much will he have in 1 year?

Mathematics
1 answer:
ladessa [460]3 years ago
3 0

Answer:

$ 728

Step-by-step explanation:

Amount of Money Cody has = $700

Simple Interest = 4%

As it is know that interest is always given on annually basis so

Amount of profit he have in one year = Money he have right now * interest

                                                              =700 * 4%

                                                              =700 * \frac{4}{100}

                                                               = $ 28

After one year he will have = total money at that time + Profit

                                              = 700 + 28

                                              = $ 728

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Daniel invests $2,037 in a retirement account with a fixed annual interest rate of 6% compounded 6 times per year. What will the
notka56 [123]

Answer:

\$5294.72

Step-by-step explanation:

GIVEN: Daniel invests \$2,037 in a retirement account with a fixed annual interest rate of 6\% compounded 6 times per year.

TO FIND: What will the account balance be after 16 years

SOLUTION:

Amount invested by Daniel =\$2037

Annual interest rate =6\%      

Total amount generated by compound interest is  =P(1+\frac{r}{n})^n^t

Here Principle amount P=\$2037

rate of interest r=6\%

number of times compounding done in a year n=6

total duration of time nt=16\text{ years}

putting values we get

=2037(1+\frac{6}{6\times100})^1^6

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4 0
3 years ago
What are the features of the parabola modeled by the equation f(x) = x2 - 114x ?
notsponge [240]

Answer:

Answers are in bold type

Step-by-step explanation:

f(x) = x^{2} -144x

The parabola opens up, so has a minimum at the vertex.

Let (h, k) be the vertex

h = -b/2a = - (-144)/2(1) = 57

k = 57^2 - 144(57) = 3249 - 6498 = -3249

Therefore, the vertex is (57, -3249)

The minimum value is -3249

The domain is the set of real numbers.  

The  range = {y | y ≥ -3249}

The function decreases when -∞ < x < 57  and increases when 57 > x > ∞

The x - intercepts:  x^{2} -144x = 0

                                x(x - 114x) = 0

                                x = 0 or x = 114

x-intercepts are (0, 0) and (0, 114)

When x = 0, then we get the y-intercept.  So, 0^2 - 114(0) = 0

y-intercept is (0, 0)

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3 years ago
Luke started a weight-loss program. The first week, he lost X pounds. the second week he lost 3/2 pounds less then 3/2 times the
irga5000 [103]

Luke started a weight-loss program.

The first week, he lost X pounds.

the second week he lost 3/2 pounds less then 3/2 times the pounds he lost the first week. so, he lost 3/2 x - 3/2

The third week, he lost 1 more pound than 3/4 of the pounds he lost the first week. so, he lost 3/4 x + 1

So, over 3 weeks he lost :

x + (3/2 x - 3/2) + (3/4 x + 1) = 13/4 x - 1/2

=========================================================

Liam started the program when Luke did.

The first week, he lost 1 pound less than 3/2 times the pounds luke lost the first week. so, he lost (3/2 x - 1)

The second week, he lost 4 pounds less than 5/2 times the pounds luke lost the first week. so ,he lost (5/2 x - 4)

The third week, he lost 1/2 more than 5/4 times the pounds luke lost the first week. so, he lost, ( 5/4 x + 1/2)

The expression for Liam's weight loss over the three weeks is =

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=============================================================

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So, equating the number of pounds lost by each one of them

so,

13/4 x - 1/2 = 21/4 x - 9/2

solve for x

13/4 x - 21/4 x = -9/2 + 1/2

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divide both sides by -2

so,

x = -4/-2 = 2

so,

The number of pounds luke lost in the fist week is 2 pounds

=============================================================

4. The number of pounds luke and liam each lost over the three weeks is

= 13/4 * 2 - 1/2 = 6 pounds

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The answer of the question which you asked above is
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Answer:

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