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11111nata11111 [884]
2 years ago
12

PROM Caleb manages the budget for his school's junior prom. His class has spent $1250 for the prom venue, $625 for a DJ, and $14

70 for
decorations. They will also serve dinner before the dance, which costs $12 per student. If he wants to keep the cost of prom tickets less than
$20, how many students will need to buy tickets?
Mathematics
1 answer:
Bogdan [553]2 years ago
5 0

The number of students that will need to buy the tickets is 419.

<h3>How many students will need to buy tickets?</h3>

The equation that can be formed from the information provided in the question is:

$20s < $1250 + $625 + $1470 + $12s

Where s represents the number of students

$20s < $3345 + $12s

$20 - $12s < $3345

$8s < $3345

s < $3345  / $8

s < 419

To learn more about inequality, please check: brainly.com/question/5031619

#SPJ1

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Sholpan [36]
A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
d^2=3^2+2^2
d^2=9+4
d^2=13
d= \sqrt{13}
We can conclude that the distance between my house and the movie theater is \sqrt{13}

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
d^2=6^2+5^2
d^2=36+25
d^2=61
d= \sqrt{61}
We can conclude that the distance between the police station and the airport is \sqrt{61}

C. Distance form the park to the Fire Station:
d^2=3^2+1^2
d^2=9+1
d^2=10
d= \sqrt{10}
We can conclude that the distance from the park to the Fire Station is \sqrt{10}

Distance from the stadium to the mall:
d^2=2^2+1^2
d^2=4+1
d^2=5
d= \sqrt{5}
We can conclude that the distance from the stadium to the mall is \sqrt{5}

D. What is the distance between your house and the mall?
Answer:
d^2=4^2+4^2
d^2=16+16
d^2=32
d= \sqrt{32}
d=4 \sqrt{2}
We can conclude that the distance between my house and the mall is 4 \sqrt{2}

What is the distance between the movie theater and the school?
answer:
d^2=3^2+1^2
d^2=9+1
d^2=10
d= \sqrt{10}
We can conclude that the distance between the movie theater and the school is \sqrt{10}

7 0
3 years ago
Find BC<br> Round to the nearest tenth.<br> 7<br> 140°<br> B<br> 13
OlgaM077 [116]

Answer:

The answer is

Step-by-step explanation:

This is from khan academy. so You need to watch a video on khan academy to get help.

6 0
3 years ago
A professional soccer player kicked a ball across the field. The ball’s height, in meters, is modeled by the function graphed be
pantera1 [17]

Answer:

Hey there!

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6 0
3 years ago
If two polygons are similar, must they also be congruent?
NISA [10]

Answer:

I think No

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4 0
3 years ago
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11111nata11111 [884]

Answer:

22.99 inches

Step-by-step explanation:

According to problem, given data are as follows:

Fabric used for headband = 595.56 inches

Number of headbands made = 39 + 3 = 42

So, Fabric used per headband = 595.56 ÷ 42 = 14.18 inches per headband

Similarly, Fabric used for wristband = 343.59 inches

Number of wristbands made = 39

So, Fabric used per wristband = 343.59 ÷ 39 = 8.81 inches per wristband

So, Fabric used for each player = 14.18 inches + 8.81 inches

= 22.99 inches

3 0
3 years ago
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