The exterior angle at the intersection of the tangent and secant has a measure that is half the difference between the intercepted arcs.
... ((10x+20) -80)/2 = 2x+15
... 5x -30 = 2x +15
... 3x = 45
... x = 15
So, the unknown arc to the right has measure
.. 10x + 20 = 10·15 +20 = 170
And the arcs of the circle total 360°.
... 80 + z + 170 = 360
... z = 360 - 250 = 110 . . . subtract 250 from both sides
The appropriate choice for the value of z is
... B. 110
Answer:
D: {(-5, -4, 2, 2, 5)}
R: {(-6, 3, 4, 1, 5)}
The relation is NOT a function.
Step-by-step explanation:
By definition:
A relation is any set of ordered pairs, which can be thought of as (input, output).
A function is a <em><u>relation</u></em> in which no two ordered pairs have the same first component (domain/input/x value) and different second components (range/output/y value).
Looking at the given points in your graph, and in listing down the domain and range, we can infer that the relation is not a function because there is an x-value (2) that has two corresponding y-values: (2, 4) (2, 1).
Another way to tell if a given set of points in a graph represents a function by doing the "Vertical line test." The graph of an equation represents y as a function of x if and only if no vertical line intersects the graph more than once. Looking at the attached image, I drew a vertical line over points (2, 4) (2, 1). The vertical line intersects the two points, which fails the vertical line test. This is an indication that the given relation is not a function.
Answer:
<em>Your Interquartile range (IQR) would be 19.</em>
Step-by-step explanation:
-5, 1, 3, 7, 8, 10, 32, 36
Median: 7.5
Lower quartile: 2
Upper quartile: 21
Interquartile range: 21 - 2 = 19
Answer:
1 + ln 2 - ln x
Step-by-step explanation:
ln ( 2e /x)
We know that ln ( a/b) = ln ( a) - ln (b)
ln (2e) - ln (x)
We also know that ln ( a*b) = ln a + ln b
ln ( 2) + ln e - ln x
We know that the ln e = 1
ln 2 + 1 - ln x
Changing the order
1 + ln 2 - ln x
3√10^4x is equivalent to -√10 3/4^x and -4√10^3x they are all equivalent