edward travels 150 kilometers due west and then 200 kilometers in a direction 60 degrees north of west.what is his displacement
1 answer:
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Answer:
Explanation:
Using the tension in the spring and the force of the tension can by describe by
T = kx
, T = mg
Therefore:
With two springs, let, T1 be the tension in each spring, x1 be the extension of each spring. The spring constant of each spring is 2k so:
Solve to x1
Use pythagorean theorem
to find the opposite side, which is 7.3
so then you can just use inverse sinA=7.3/10 which equals 46.9 degrees
to find the opposite side, which is 7.3
so then you can just use inverse sinA=7.3/10 which equals 46.9 degrees
Answer:
The true course: north of east
The ground speed of the plane: 96.68 m/s
Explanation:
Given:
= velocity of wind =
= velocity of plane in still air =
Assume:
= resultant velocity of the plane
= direction of the plane with the east
Since the resultant is the vector addition of all the vectors. So, the resultant velocity of the plane will be the vector sum of the wind velocity and the plane velocity in still air.
Let us find the direction of this resultant velocity with respect to east direction:
This means the the true course of the plane is in the direction of north of east.
The ground speed will be the magnitude of the resultant velocity of the plane.
Hence, the ground speed of the plane is 96.68 km/h.