- Mass of the car (m) = 2000 Kg
- Initial velocity (u) = 15 m/s
- Force (F) = 10000 N
- Time (t) = 3 s
- Let the acceleration be a.
- By using the formula, F = ma, we get,
- 10000 N = 2000 Kg × a
- or, a = 10000 N ÷ 2000 Kg
- or, a = 5 m/s^2
- Let the final velocity be v.
- By using the formula, v = u + at, we get,
- v = 15 m/s + 5 m/s^2 × 3 s
- or, v = 15 m/s + 15 m/s
- or, v = 30 m/s
<u>Answer</u><u>:</u>
<em><u>The </u></em><em><u>new </u></em><em><u>sp</u></em><em><u>e</u></em><em><u>ed </u></em><em><u>of </u></em><em><u>the </u></em><em><u>car </u></em><em><u>is </u></em><em><u>3</u></em><em><u>0</u></em><em><u> </u></em><em><u>m/</u></em><em><u>s.</u></em>
Hope you could get an idea from here.
Doubt clarification - use comment section.
Answer:
Force of static friction between the two surfaces
Explanation:
When two surfaces come into contact, they exert a force that resist the sliding of the two surfaces. This force is called static friction.
This force is given by the relation
Where,
μ - coefficient of static friction
η - normal force acting on the body
When a force acts on a body placed on a rough surface, it doesn't do any work if the applied force was less than the force of static friction.
So, in order to move the body, the applied force should be greater than the force of static friction.
B. The resistance is directly proportional to length and inversely proportional to cross sectional area
Answer:
17.55 m/s²
Explanation:
Parameters given:
Mass of Krypton, M = 7.6 * 10^23 kg
Radius, R = 1.7 * 10^6 m
Gravitational constant, G = 6.6726 * 10^(-11) Nm²/kg²
Acceleration due to gravity of planet of mass M is given as:
g = GM/R²
Since the object is close to the surface of Krypton, we can say that the distance from the Centre of Krypton is the radius of the planet Krypton.
Therefore,
g = (6.6726 * 10^(-11) * 7.6 * 10^23)/(1.7 * 10^6)²
g = 17.55 m/s²
Answer:
Wave A
<em>I</em><em> </em><em>hope this</em><em> </em><em>helps</em><em> </em>
