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nydimaria [60]
2 years ago
14

edward travels 150 kilometers due west and then 200 kilometers in a direction 60 degrees north of west.what is his displacement

in the westerly direction?
Physics
1 answer:
Naily [24]2 years ago
3 0

The displacement of Edward in the westerly direction is determined as 338.32 km.

<h3>What is displacement of Edward?</h3>

The displacement of Edward can be determined from different methods of vector addition. The method applied here is triangular method.

The angle between the 200 km north west and 150 km west = 60 + 90 = 150⁰

The displacement is the side of the triangle facing 150⁰ = R

R² = a² + b² - 2abcosR

R² = 150² + 200²  - (2x 150 x 200)xcos(150)

R² = 62,500 - (-51,961.52)

R² = 114,461.52

R = 338.32 km

Learn more about displacement here: brainly.com/question/321442

#SPJ1

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<h2>Answer: 5 cm</h2>

In convex mirrors the focus is virtual and the focal distance is negative. This is how the reflected rays diverge and only their extensions are cut at a point on the main axis, resulting in a virtual image of the real object .

The Mirror equation is:  

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}    (1)  

Where:  

f=-6cm is the focal distance  

u=12cm is the distance between the object and the mirror  

v is the distance between the image and the mirror

We already know the values of f and u, let's find v from (1):  

v=\frac{u.f}{u-f}    (2)  

v=\frac{(12cm)(-6cm)}{12cm-(-6cm)}

v=-4cm   (3)

On the other hand, the magnification m of the image is given by the following equations:  

m=-\frac{v}{u}   (4)

m=\frac{h_{i}}{h_{o}}   (5)

Where:

h_{i} is the image height  

h_{o}=15cm is the object height

Now, if we want to find the image height, we firstlu have to find m from (4), substitute it on (5) and find h_{i}:

Substituting  (3) in (4):

m=-\frac{-4cm}{12cm}  

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Substituting  (6) in (5):

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h_{i}=\frac{15cm}{3}

Finally we obtain the value of the height of the image produced by the mirror:

h_{i}=5cm

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