Question

Select the two binomials that are factors of 64x^2 – 36.

Answer 1

64x² - 36 factors to be (8x + 6)(8x - 6)

Option C is your answer. 

HOWEVER, I cannot tell what the operation is supposed to be performed because of the way it is showing up above (see attached pic). So I can also just simplify it.

64x² - 36 becomes 4(16x² - 9) or 4(4x - 3)(4x + 3)

64x² + 36 becomes 4(16x² + 9)

Answer 2

Answer:

8x+6 and 8x-6

C and D are correct.

Step-by-step explanation:

Given: $64x^2-36$

We need to factor it and choose two polynomial of factored form.

$\Rightarrow 64x^2-36$

First we write as perfect square each term and difference of square

$\Rightarrow (8x)^2-6^2$

Because 64 = 8x8   and 36=6x6

Using difference of square identity,

$a^2-b^2=(a+b)(a-b)$

$\Rightarrow (8x+6)(8x-6)$

Thus, Two factors are 8x+6 and 8x-6

Two binomial of factors are 8x+6 and 8x-6