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Rudik [331]
3 years ago
9

Select the two binomials that are factors of 64x^2 – 36.

Mathematics
2 answers:
lara [203]3 years ago
7 0
64x² - 36 factors to be (8x + 6)(8x - 6)

Option C is your answer. 

HOWEVER, I cannot tell what the operation is supposed to be performed because of the way it is showing up above (see attached pic). So I can also just simplify it.

64x² - 36 becomes 4(16x² - 9) or 4(4x - 3)(4x + 3)

64x² + 36 becomes 4(16x² + 9)

ira [324]3 years ago
3 0

Answer:

8x+6 and 8x-6

C and D are correct.

Step-by-step explanation:

Given: 64x^2-36

We need to factor it and choose two polynomial of factored form.

\Rightarrow 64x^2-36

First we write as perfect square each term and difference of square

\Rightarrow (8x)^2-6^2

Because 64 = 8x8   and 36=6x6

Using difference of square identity,

a^2-b^2=(a+b)(a-b)

\Rightarrow (8x+6)(8x-6)

Thus, Two factors are 8x+6 and 8x-6

Two binomial of factors are 8x+6 and 8x-6

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