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3 years ago

6

Here is a picture showing how two magnets will stick to one another when opposite poles align. When these magnets are pulled sli

ghtly apart, does the attractive force between them still exist?
A)Yes, but the new attractive force is due to gravity.
B)No, since they are not touching, no force is at work.
C)Yes, even though they are not touching, they are pulling on one another.
D)No, when the magnets are apart, they exert a repulsive force on one another.

2 answers:

7nadin3 [17]3 years ago

7 0

Answer:

C

Explanation:

A magnetic field exerts its force beyond just direct touch.

ser-zykov [4K]3 years ago

7 0

The correct answer is C!

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1 year ago

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3 years ago

Problem One: A beam of red light (656 nm) enters from air into the side of a glass and then into water. wavelength, c. and speed

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Answer:

Part a)

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Part b)

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$v_w = 2.25 \times 10^8 m/s$

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Explanation:

Part a)

frequency of light will not change with change in medium but it will depend on the source only

so here frequency of light will remain same in both water and glass and it will be same as that in air

$f = \frac{v}{\lambda}$

$f = \frac{3 \times 10^8}{656 \times 10^{-9}}$

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Part b)

As we know that the refractive index of water is given as

$\mu_w = 4/3$

so the wavelength in the water medium is given as

$\lambda_w = \frac{\lambda}{\mu_w}$

$\lambda_w = \frac{656 nm}{4/3}$

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Similarly the refractive index of glass is given as

$\mu_w = 3/2$

so the wavelength in the glass medium is given as

$\lambda_g = \frac{\lambda}{\mu_g}$

$\lambda_g = \frac{656 nm}{3/2}$

$\lambda_g = 437.3 nm$

Part c)

Speed of the wave in water is given as

$v_w = \frac{c}{\mu_w}$

$v_w = \frac{3 \times 10^8}{4/3}$

$v_w = 2.25 \times 10^8 m/s$

Speed of the wave in glass is given as

$v_g = \frac{c}{\mu_g}$

$v_g = \frac{3 \times 10^8}{3/2}$

$v_g = 2 \times 10^8 m/s$

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3 years ago