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Sauron [17]
3 years ago
13

Use Hooke's Law, which states that the distance a spring stretches (or compresses) from its natural, or equilibrium, length vari

es directly as the applied force on the spring. A force of 265 newtons stretches a spring 0.15 meter. (a) What force stretches the spring 0.4 meter
Physics
1 answer:
Phantasy [73]3 years ago
6 0

Answer:

706.68 N

Explanation:

By Hooke's law,

F = ke

k=\dfrac{F}{e}

Using the values in the question,

k=\dfrac{265\text{ N}}{0.15 \text{ m}}=1766.7\text{ N/m}

When e = 0.4 m,

F = 1766.7\text{ N/m}\times0.4\text{ m}=706.68\text{ N}

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0.544 eV

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3 years ago
Un bloque de 750 kg es empujado hacia arriba por una pista inclinada 15º respecto de la horizontal. El coeficiente de rozamiento
kotegsom [21]

Answer:

4776.98 N is the minimum force to start the rise.  

Explanation:

We can use the first Newton's law to find the minimum force to move the block.

So we will have:

F-W_{x}-F_{f}=0

Where:

  • F is the force
  • W(x) is the weight of the block in the x direction, W = mg*sin(15)
  • F(f) is the static friction force (F(f) = μN), μ is the static friction coefficient 0.4.

F=W_{x}+F_{f}=mgsin(15)+\mu N

F=mgsin(15)+\mu mgcos(15)

F=mg(sin(15)+\mu cos(15))

F=750*9.81(sin(15)+0.4*cos(15))

F=4776.98 N

Therefore 4776.98 N is the minimum force to move the block.

I hope it helps you!

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