Answer:
Step-by-step explanation:
Given:
The implicit equation is given as:
In implicit differentiation, we treat 'y' as a function of 'x' and differentiate both sides of the equation with respect to 'x' and then collect all the 
together and finally solve for .
So, differentiating both sides of the above equation with respect to 'x'. This gives,
Therefore, the derivative implicitly is:
If your teacher do not put the value of the q all the letters will be 1 so: 1+5=6 (after you just simplify)
Y= a(x-3)^2+6
2= a(0-3)^2+6
2=a(-3)^2+6
2=a(9)+6
2-6=9a
-4=9a
-4/9=a
Therefore the equation in vertex form is
y = -4/9 (x-3)^2+6
Y = -4x - 2
P (-16, -11)
a = -4, b = 0, c = -2
m = -a/b
m = -(-4)/(-2)
m = 4/(-2)
m = -2
y-yo = m(x-xo)
y-(-11) = -2[x-(-16)]
y+11 = -2(x+16)
y+11 = -2x-32
2x+y+11+32 = 0
2x+y+43 = 0
A outra questão é semelhante.
Y = mx + c
-4 = 2(3) + c
-4 = 6 + c
-10 = c
y = mx + c
y = 2x - 10
Hence, the equation is y=2x-10.
