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koban [17]
1 year ago
10

Determine the number of outcomes in the event. Decide whether the event is a simple event or not. A computer is used to select r

andomly a number between 1 and 9, inclusive. Event C is selecting a number greater than 8. Event C has outcome(s). Is the event a simple event? because event C has one outcome.
​
Mathematics
1 answer:
Oliga [24]1 year ago
7 0

The probability of selecting a number greater than 8 will be p=\dfrac{1}{9}.

<h3>What is probability?</h3>

Probability is defined as the ratio of the number of favourable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

The number of outcomes = { 1,2,3,4,5,6,7,8,9 } = Counts = 9

Favourable outcomes = { 9 } = counts = 1

The probability will be given as:-

P = \dfrac{1}{9}

Therefore the probability of selecting a number greater than 8 will be p=\dfrac{1}{9}.

To know more about probability follow

brainly.com/question/24756209

#SPJ1

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PLEASE HELP ME OUT!!!!!!!!!!
Semmy [17]

Answer:

Exponential

Step-by-step explanation:

- Linear is a straight line no matter what.

- Quadratic lines makes a u or v shape that opens up, down, left, or right.

- Exponential is like a slanted 45° clockwise u and a bit stretched horizontally.

- Square root lines on a graph, looks more like a slanted L 90° clockwise.

- Inverse Variation would show its inverse, same as a mirror, it would be something similar to a hyperbola.

Hope This Helps!

6 0
2 years ago
In parallelogram DEFG, DH = x + 5, HF = 2y, GH = 3x – 1, and HE = 5y + 4. Find the values of x and y.
earnstyle [38]
The diagonals of a parallelogram bisect each other.

DH = HF and GH = HE

x + 5 = 2y
3x - 1 = 5y + 4

Solve the first equation for x.
x = 2y - 5

Now substitute 2y - 5 for x in the second equation.

3(2y - 5) - 1 = 5y + 4

6y - 15 - 1 = 5y + 4

6y - 16 = 5y + 4

y = 20

Now substitute 20 for y in the first original equation.

x + 5 = 2y

x + 5 = 2(20)

x + 5 = 40

x = 35

Answer: x = 35 and y = 20
4 0
3 years ago
Read 2 more answers
A sphere has a volume of V=900 in cubed. What is the surface area?
ycow [4]
First, we must solve for the radius of the sphere:
V=\frac{4}{3}\pir^{3}
r=(3\frac{V}{4 \pi })^{ \frac{1}{3} }
r=(3*\frac{900}{4 \pi })^{ \frac{1}{3} }
r≈5.99

Second, we must solve for surface area:
A=4\pir^{2}
A=4*\pi*5.99^{2}
A≈450.88 in^{2}
4 0
3 years ago
What is the simplified form of the following expression? 2 Sqrt 18+3 Sqrt 2 + Sqrt 162
grandymaker [24]

Answer:

18√2

Step-by-step explanation:

2√18 + 3√2 + √162

= 2√(9 * 2) + 3√2 + √(81 * 2)

= (2 * 3)√2 + 3√2 + 9√2

= 6√2 + 3√2 + 9√2

= (6 + 3 + 9)√2

= 18√2

6 0
3 years ago
Read 2 more answers
For each part, give a relation that satisfies the condition. a. Reflexive and symmetric but not transitive b. Reflexive and tran
Vesnalui [34]

Answer:

For the set X = {a, b, c}, the following three relations satisfy the required conditions in (a), (b) and (c) respectively.

(a) R = {(a,a), (b,b), (c, c), (a, b), (b, a), (b, c), (c, b)} is reflexive and symmetric but not transitive .

(b) R = {(a, a), (b, b), (c, c), (a, b)} is reflexive and transitive but not symmetric .

(c) R = {(a,a), (a, b), (b, a)} is symmetric and transitive but not reflexive .

Step-by-step explanation:

Before, we go on to check these relations for the desired properties, let us define what it means for a relation to be reflexive, symmetric or transitive.

Given a relation R on a set X,

R is said to be reflexive if for every a \in X, (a,a) \in R.

R is said to be symmetric if for every (a, b) \in R, (b, a) \in R.

R is said to be transitive if (a, b) \in R and (b, c) \in R, then (a, c) \in R.

(a) Let R = {(a,a), (b,b), (c, c), (a, b), (b, a), (b, c), (c, b)}.

Reflexive: (a, a), (b, b), (c, c) \in R

Therefore, R is reflexive.

Symmetric: (a, b) \in R \implies (b, a) \in R

Therefore R is symmetric.

Transitive: (a, b) \in R \ and \ (b, c) \in R but but (a,c) is not in  R.

Therefore, R is not transitive.

Therefore, R is reflexive and symmetric but not transitive .

(b) R = {(a, a), (b, b), (c, c), (a, b)}

Reflexive: (a, a), (b, b) \ and \ (c, c) \in R

Therefore, R is reflexive.

Symmetric: (a, b) \in R \ but \ (b, a) \not \in R

Therefore R is not symmetric.

Transitive: (a, a), (a, b) \in R and (a, b) \in R.

Therefore, R is transitive.

Therefore, R is reflexive and transitive but not symmetric .

(c) R = {(a,a), (a, b), (b, a)}

Reflexive: (a, a) \in R but (b, b) and (c, c) are not in R

R must contain all ordered pairs of the form (x, x) for all x in R to be considered reflexive.

Therefore, R is not reflexive.

Symmetric: (a, b) \in R and (b, a) \in R

Therefore R is symmetric.

Transitive: (a, a), (a, b) \in R and (a, b) \in R.

Therefore, R is transitive.

Therefore, R is symmetric and transitive but not reflexive .

4 0
3 years ago
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