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a_sh-v [17]
4 years ago
9

Can you please help me please =( I beg you

Mathematics
2 answers:
kherson [118]4 years ago
7 0

Answer:

<h2>steps A & B</h2><h2 />

Step-by-step explanation:

5x + 9 = 2x - 3

subtract 2x from both sides

5x - 2x + 9 = 2x - 2x - 3

simplify:

3x + 9 = -3

subtract 9 from both sides:

3x + 9 - 9 = -3 - 12

simplify:

3x = -12

divide 3 on both sides:

<u>3x</u> = <u>- 12 </u>

3        3

simplify:

x = -4

emmasim [6.3K]4 years ago
6 0

Answer:

I think he made a mastake a step 3

Step-by-step explanation:

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Please help :( Im desperate
ki77a [65]

Answer:

(2,4)

Step-by-step explanation:

When graphed the lines intersect at point (2,4) which is the solution.

8 0
3 years ago
Bab needs help please!
schepotkina [342]
Answer: it's 3.14 in^3
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3 years ago
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igomit [66]

Answer: 8:05

Step-by-step explanation:

8 0
2 years ago
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So far this year, the average monthly revenue at Lexington Times is 50,711. That is 5% less than the monthly average was last ye
SOVA2 [1]

53,380 was the average last year .

<u>Step-by-step explanation:</u>

Here we have , So far this year, the average monthly revenue at Lexington Times is 50,711. That is 5% less than the monthly average was last year. We need to find that  What was the average last year . Let's find out:

Let the monthly average was last year be x , According to question the average monthly revenue at Lexington Times is 50,711 but , That is 5% less than the monthly average was last year . Following equation for above scenario is :

⇒ x-\frac{5(x)}{100}=50711

⇒ \frac{100x-5x}{100}=50711

⇒ \frac{95x}{100}=50711

⇒ \frac{95x(100)}{100(95)}=\frac{50711(100)}{95}

⇒ x=\frac{50711(100)}{95}

⇒ x=53380

Therefore , 53,380 was the average last year .

7 0
4 years ago
The price of tomatoes went from $1.12 per pound to $1.96 per pound in 3 years. find the rate of change of the price of tomatoes.
ad-work [718]

\bf \begin{array}{|cc|ll} \cline{1-2} \stackrel{x}{year}&\stackrel{y}{price}\\ \cline{1-2} 0&1.12\\ 3&1.96\\ \cline{1-2} \end{array}~\hspace{10em} (\stackrel{x_1}{0}~,~\stackrel{y_1}{1.12})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{1.96}) \\\\\\ \stackrel{\textit{rate of change}}{slope = m\implies} \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1.96-1.12}{3-0}\implies \cfrac{0.84}{3}\implies 0.28

7 0
3 years ago
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