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katen-ka-za [31]
2 years ago
11

Car 2 passes car 1. To a stationary observer, car 1 has a velocity of 28 m/s to the east and car 2 has a velocity of 33 m/s to t

he east. How much time will pass before car 2 is 14 m ahead of car 1?
Mathematics
1 answer:
Alla [95]2 years ago
8 0

Answer:

2.8 s

Step-by-step explanation:

33x = 28x + 14(m)

5x = 14(m)

<em>x = 2.8(s)</em>

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Answer:

a   10 yd   2ft  7 in

b 10 yd  1 ft  2 in

c  99 yd

d.  4840 sq  yd  7 sq ft  119 sq in  

Step-by-step explanation:

a.      2 ft. 5 in. +

9 yd. 3 ft. 2 in.

---------------------

9 yd   5ft   7 in

but 3 ft = 1yd

9 yd   5ft   7 in

+1yd   - 3ft

---------------------------

10 yd   2ft  7 in



b. 4 yd. 8 in

+ 6 yd. 6 in.

----------------------

10 yd   14 in

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10 yd       14 in

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---------------------

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c. 29 yd. 2 ft. 11 in.

  55 yd. 1 ft. 10 in.

+ 13 yd. 1 ft. 3 in.  

--------------------------

97 yd   4 ft   24 in

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97 yd   4 ft   24 in

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--------------------------------

97 yd   6ft

3 ft = 1yd

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97 yd   6ft

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---------------------

99 yd


d. 4,839 sq. yd. 8 sq. ft. 139 sq. in.

                      + 7 sq. ft. 124 sq. in.

--------------------------------------------------

  4839  sq yd  15 sq ft   263 sq in

12*12 = 144 sq in = 1 sq ft

 4839  sq yd  15 sq ft   263 sq in

                       + 1 sq ft  - 144 sq in

--------------------------------------------------

4839  sq yd  16 sq ft  119 sq in

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4839  sq yd  16 sq ft  119 sq in

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----------------------------------------------

4840 sq  yd  7 sq ft  119 sq in              

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