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katen-ka-za [31]

2 years ago

11

Car 2 passes car 1. To a stationary observer, car 1 has a velocity of 28 m/s to the east and car 2 has a velocity of 33 m/s to t

he east. How much time will pass before car 2 is 14 m ahead of car 1?

1 answer:

Alla [95]2 years ago

8 0

Answer:

2.8 s

Step-by-step explanation:

33x = 28x + 14(m)

5x = 14(m)

<em>x = 2.8(s)</em>

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How do I find the missing angle?

Sveta_85 [38]

To find the missing angle first we need to fill in the other angles.
If we look at the 128 its on a straight line that is separated by another straight line so to get the angle on the other side of the line we need to subtract 128 from 180 which is 52.
The same goes for 160 so 180-160 = 20
And again the same for 60 so 180-60 = 120
So now that we have 2 out of 3 angles in the triangle we can figure out the final one by subtracting 120 and 20 from 180 (because theres 180 degrees in a triangle) which equals 40
Now if we look at the 40 degrees the other side is its opposite which makes it the same degree, and now we once again have 2 out of the 3 angles in a triangle so go to the triangle with 52 degrees and 40 degrees and subtract them from 180 which would be 88 degrees.
Now we subtract 88 from 180 to get the missing angle that we need (because its on another straight line thats been separated by another straight line) which equals 92

So the answer to your question is 92 degrees

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3 years ago

Plot points (3,-8) and (3,4) on the coordinate plane

zimovet [89]

Answer:

Slope is undefined

Step-by-step explanation:

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3 years ago

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soldi70 [24.7K]

The answer is C, 10 7/15 !

7 0

3 years ago

Find a vector equation and parametric equations for the line. (Use the parameter t.) The line through the point (0, 15, −6) and

Len [333]

<x = 0 + 2t, y = 15 - 3t, z = -6 + 7t> is the vector parametric equation of the line parallel to the given one and that passes through the point (0, 15, −6).

According to the statement

we have to find that the vector equation with the help of the given line equation and the points.

So, For this purpose, we know that the

A vector equation is an equation involving a linear combination of vectors with possibly unknown coefficients.

And the given points is (0, 15, −6) and the lines

x = −1 + 2t,

y = 6 − 3t,

z = 3 + 7t

From these equation of lines:

Let a = -1 and b = 6 and c = 3

Then

Now, if we want this line to pass through the point (0, 15, -6), then we can replace the correspondent values in the constant term for each equation:

So, Put it in the given equations then

x = 0 + 2t and y = 15 - 3t and z = -6 + 7t

and the vector equation become

<x = 0 + 2t, y = 15 - 3t, z = -6 + 7t>

So, <x = 0 + 2t, y = 15 - 3t, z = -6 + 7t> is the vector parametric equation of the line parallel to the given one and that passes through the point (0, 15, −6).

Learn more about vector parametric equation here

brainly.com/question/17088529

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7 0

1 year ago

Given: measure 1, measure 2, measure 3, and measure 4 formed by two intersecting segments Prove: measure 1 and measure 3 are con

lesantik [10]

Step-by-step explanation:

<h3><u>Note</u>: </h3>

The text below that are formatted in bold and underlined font are the solutions to the missing boxes in your given problem.

<h3><u>Explanation:</u></h3>

Given that ∠1, ∠2, ∠3, and ∠4 are formed by two intersecting segments, and that:

∠1 and ∠2 form a linear pair

∠2 and ∠3 form a linear pair

These linear pair relationships suggest that by the Linear Pair Postulate:

<u>∠1 and ∠2 are supplementary</u>. ⇒ Linear Pair Postulate

<u>∠2 and ∠3 are supplementary</u>. ⇒ Linear Pair Postulate

m∠2 + m∠ 3 = 180° ⇒ <u>Definition of supplementary angles</u>.

<u>m∠1 + m∠3 = m∠2 + m∠ 3</u> ⇒ Substitution Property of Equality.

m∠1 = m∠3 ⇒ <u>Subtraction Property of Equality</u>.

4 0

3 years ago