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katen-ka-za [31]
2 years ago
11

Car 2 passes car 1. To a stationary observer, car 1 has a velocity of 28 m/s to the east and car 2 has a velocity of 33 m/s to t

he east. How much time will pass before car 2 is 14 m ahead of car 1?
Mathematics
1 answer:
Alla [95]2 years ago
8 0

Answer:

2.8 s

Step-by-step explanation:

33x = 28x + 14(m)

5x = 14(m)

<em>x = 2.8(s)</em>

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Answer:

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Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: y=mx+b where <em>m</em> is the slope and <em>b</em> is the y-intercept (the value of y when the line crosses the y-axis)

Given that the slope is 3, we can plug this into y=mx+b as <em>m</em>:

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Now, to solve for <em>b</em>, simply plug in the given point:

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Therefore, the y-intercept is 5. Plug this back into the equation:

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I hope this helps!

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Step-by-step explanation:

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Now combine 75/48 and 35/48, obtaining 110/48, or 55/24.


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