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aliya0001 [1]
3 years ago
13

5X(squared) - 4X = 6 Solve for X

Mathematics
2 answers:
Leto [7]3 years ago
7 0
5x^2 - 4x = 6

<span>5x^2 - 4x - 6 = 0 
</span>
Use the quadratic equation (I attached a photo of it)
Now, you can use this formula to know what to plug into the formula:
ax^2<span> + </span>bx<span> + </span>c<span> = 0
</span>
The easiest way to understand what to plug in is just to put your equation right next to this one:
ax^2 + bx + c<span> = 0
</span><span>5x^2 - 4x - 6 = 0 
</span>So, 
A= 5
B= -4
C= -6

So, plug it in a solve. Remember you cannot take the square root of a negative number or 0. If it does not come to a number that is easily square rooted you must simplify it to this for example: 5 times the square root of 7.  Also, your answer will be x plus or minus a number. This means that the number could be either negative or positive. <span>If you have anymore questions let me know.</span>

Andrews [41]3 years ago
7 0

Answer:

x=\frac{2+\sqrt{34}}{5} and x=\frac{2-\sqrt{34}}{5}

Step-by-step explanation:

5x^2-4x=6

To solve for x , we need to get 0 on the right side

Subtract 6 on both sides

5x^2-4x-6=0

Factor the left hand side

To solve for x , we apply quadratic formula

x=\frac{-b+-\sqrt{b^2-4ac}}{2a}

The value of a=5, b=-4, c= -6

x=\frac{4+-\sqrt{(-4)^2-4(5)(-6)}}{2(5)}

x=\frac{4+-\sqrt{136}}{10}

x=\frac{4+-2\sqrt{34}}{10}

Divide top and bottom by 2

x=\frac{2+-\sqrt{34}}{5}

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What is the balanced equation for the reaction (NH4)2SO4+SrCl2--&gt;
steposvetlana [31]
(NH4)2SO4+SrCl2--><span>(NH4)2Cl2 + SrSO4

The reaction side are both aquas and the product is aquas and a solid precipitate. </span>
7 0
3 years ago
Use the graph below to determine a1 and d for the sequence. graphed sequence showing point 1, negative 10, point 2, negative 7,
Sonja [21]

Answer:

a_1=-10

d=3

Step-by-step explanation:

we know that                              

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant, and this constant is called the common difference (d)

In this problem we have the ordered pairs

(1,-10),(2,-7),(3,-4),(4,-1),(5,2),(6,5)                      

Let                                          

a_1=-10\\a_2=-7\\a_3=-4\\a_4=-1\\a_5=2\\a_6=5

Find the difference between one term and the next

a_2-a_1=-7-(-10)=3              

a_3-a_2=-4-(-7)=3                  

a_4-a_3=-1-(-4)=3                        

a_5-a_4=2-(-1)=3                              

a_6-a_5=5-2=3                                                        

The difference between one term and the next is a constant        

This constant is the common difference                  

so                                                                                                                                  

The sequence graphed is an Arithmetic Sequence                    

therefore                                                                                    

The first term is a_1=-10                                    

The common difference is equal to d=3          

4 0
3 years ago
Help will give 20 points!
podryga [215]

Answer: What do you need help with?

Step-by-step explanation: I can help with anything.

6 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B125%20%7D%20-%20%5Csqrt%7B180%7D%20%2B%20%5Csqrt%7B45%7D%20" id="TexFormula1" tit
Kobotan [32]

Answer:

2\sqrt{5}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Simplifying the radicals

\sqrt{125} = \sqrt{25(5)} = \sqrt{25} × \sqrt{5} = 5\sqrt{5}

\sqrt{180} = \sqrt{36(5)} = \sqrt{36} × \sqrt{5} = 6\sqrt{5}

\sqrt{45} = \sqrt{9(5)} = \sqrt{9} × \sqrt{5} = 3\sqrt{5}

Thus

\sqrt{125} - \sqrt{180} +\sqrt{45}

= 5\sqrt{5} - 6\sqrt{5} + 3\sqrt{5}

= 2\sqrt{5}

3 0
3 years ago
What is the simple interest on $2500 invested at an interest rate of 6% for 2 years?
Brrunno [24]

Answer:

The simple interest is $300.

Step-by-step explanation:

<em>Find the Interest amount.</em>

I: Interest ?

P: Principle Amount $2500

R: Rate 6% = .06

T: Time Period (in years) 2 Years

<em>Convert into equation to find Simple Interest</em>

I = Prt

I = (2500)(.06)(2)

<em>Calculate</em>

I = 300

<em />

4 0
3 years ago
Read 2 more answers
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