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aliya0001 [1]
3 years ago
13

5X(squared) - 4X = 6 Solve for X

Mathematics
2 answers:
Leto [7]3 years ago
7 0
5x^2 - 4x = 6

<span>5x^2 - 4x - 6 = 0 
</span>
Use the quadratic equation (I attached a photo of it)
Now, you can use this formula to know what to plug into the formula:
ax^2<span> + </span>bx<span> + </span>c<span> = 0
</span>
The easiest way to understand what to plug in is just to put your equation right next to this one:
ax^2 + bx + c<span> = 0
</span><span>5x^2 - 4x - 6 = 0 
</span>So, 
A= 5
B= -4
C= -6

So, plug it in a solve. Remember you cannot take the square root of a negative number or 0. If it does not come to a number that is easily square rooted you must simplify it to this for example: 5 times the square root of 7.  Also, your answer will be x plus or minus a number. This means that the number could be either negative or positive. <span>If you have anymore questions let me know.</span>

Andrews [41]3 years ago
7 0

Answer:

x=\frac{2+\sqrt{34}}{5} and x=\frac{2-\sqrt{34}}{5}

Step-by-step explanation:

5x^2-4x=6

To solve for x , we need to get 0 on the right side

Subtract 6 on both sides

5x^2-4x-6=0

Factor the left hand side

To solve for x , we apply quadratic formula

x=\frac{-b+-\sqrt{b^2-4ac}}{2a}

The value of a=5, b=-4, c= -6

x=\frac{4+-\sqrt{(-4)^2-4(5)(-6)}}{2(5)}

x=\frac{4+-\sqrt{136}}{10}

x=\frac{4+-2\sqrt{34}}{10}

Divide top and bottom by 2

x=\frac{2+-\sqrt{34}}{5}

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Soloha48 [4]

Answer:

Step-by-step explanation:

vector OA=a

vector OB=b

vector OX= λ vector OA=λa

vector OY=μ vector OB=μb

a.

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4 0
4 years ago
23. Cynthia used some of the ordered pairs from the set below to make a new set.
tangare [24]

Answer:

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Step-by-step explanation:

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The third set is (2, -7), (4, -3), (-2,5), (5, 4)

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