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larisa [96]
2 years ago
10

Can someone please hepl me on tis

Mathematics
1 answer:
MA_775_DIABLO [31]2 years ago
5 0

Answer:

Answer is in pictures

Step-by-step explanation:

36=6x6 90=9x10

256+7=263 104=98+6-2

678=678 81+9=90

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T what point does the curve have maximum curvature? Y = 7ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as
Nookie1986 [14]

Formula for curvature for a well behaved curve y=f(x) is


K(x)= \frac{|{y}''|}{[1+{y}'^2]^\frac{3}{2}}


The given curve is y=7e^{x}


{y}''=7e^{x}\\ {y}'=7e^{x}


k(x)=\frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}


{k(x)}'=\frac{7(e^x)(1+49e^{2x})(49e^{2x}-\frac{1}{2})}{[1+49e^{2x}]^{3}}

For Maxima or Minima

{k(x)}'=0

7(e^x)(1+49e^{2x})(98e^{2x}-1)=0

→e^{x}=0∨ 1+49e^{2x}=0∨98e^{2x}-1=0

e^{x}=0  ,  ∧ 1+49e^{2x}=0   [not possible ∵there exists no value of x satisfying these equation]

→98e^{2x}-1=0

Solving this we get

x= -\frac{1}{2}\ln{98}

As you will evaluate {k(x})}''<0 at x=-\frac{1}{2}\ln98

So this is the point of Maxima. we get y=7×1/√98=1/√2

(x,y)=[-\frac{1}{2}\ln98,1/√2]

k(x)=\lim_{x\to\infty } \frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}

k(x)=\frac{7}{\infty}

k(x)=0







5 0
3 years ago
HELP!!<br><br> What is the area of this square, in square units?
rusak2 [61]

Answer:

Step-by-step explanation:

3x3

6 0
3 years ago
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Anna007 [38]

6 feet:10 hours

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Geometry: Solve for X
nevsk [136]
6) x= 2, angle = 90 degrees obviously
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3 years ago
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X+1/3y=4 in slope intercept form EXPLAIN
skad [1K]

Answer:

Y = 12

Step-by-step explanation:

x + 1/3y = 4

Multiply both sides of the equation by 3.

3  ⋅  1 3  ⋅  y  =  3  ⋅  4

Simplify both sides of the equation:

1. Simplify both sides of the equation.

2. Multiply 3 by 4

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Cancel the common factor of 3

Rewrite the expression.

Multiply by 1

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