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larisa [96]
2 years ago
10

Can someone please hepl me on tis

Mathematics
1 answer:
MA_775_DIABLO [31]2 years ago
5 0

Answer:

Answer is in pictures

Step-by-step explanation:

36=6x6 90=9x10

256+7=263 104=98+6-2

678=678 81+9=90

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Simplify |4n-15|=|n|
enyata [817]

Answer:        First you always get rid of parenthesis, so to get rid of that first parenthesis you multiply 4 time p, and 4 times negative three. That would then be 4p-12=2p+8. Next you get all the p's on one side and regular numbers on the other side. The easiest way to do this would be to add the -12 to the right side of the equation. To do that you need to cancel out the -12

Step-by-step explanation:

5 0
3 years ago
Select all expressions that can be subtracted from 9x to result in the expression 3x+5
Lorico [155]

Answer:

The expressions include:

6x - 5

3x - 5 + 3x

-2x - 5 + 8x

Step-by-step explanation:

Please do see the attached for more explanation

3 0
3 years ago
PLZ HELP ASAP
timurjin [86]

Answer:

1/6 16.667%

Step-by-step explanation:

less than 5

36 total outcomes

6 desired outcomes

<u>6/6=  1</u>

36/6=6

8 0
3 years ago
I need help please brainiest to the correct answer!
MrRa [10]

Answer:

wat was it

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Set up the integral needed to find the volume of the solid bounded by the hyperboloid z2 = 64 x2 y2 and by the upper nappe of th
olga2289 [7]
\begin{cases}z^2=64+x^2+y^2\\z^2=2x^2+2y^2\end{cases}

It's clear enough that the upper half of the cone falls below the upper sheet of the paraboloid, so that \sqrt{2x^2+2y^2}\le z\le\sqrt{64+x^2+y^2}. Right away you can see that converting to cylindrical coordinates will be quite advantageous.

The intersection of the two surfaces occurs as a circle:

64+x^2+y^2=2x^2+2y^2\implies64=x^2+y^2

which is parallel to the x-y plane, has radius 8, and is centered at (0,0,8\sqrt2).

The volume of this space is given by the integral

\displaystyle\iiint_S\mathrm dV=\int_{x=-8}^{x=8}\int_{y=-\sqrt{64-x^2}}^{y=\sqrt{64-x^2}}\int_{z=\sqrt{2x^2+2y^2}}^{z=\sqrt{64+x^2+y^2}}\mathrm dz\,\mathrm dy\,\mathrm dz

where S denotes the bounded space between the surfaces. Converting to cylindrical coordinates, this can be expressed as

\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=8}\int_{z=\sqrt2r}^{z=\sqrt{64+r^2}}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta

which evaluates to \dfrac{1024\pi(\sqrt2-1)}3.
5 0
3 years ago
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