All categories

2 years ago

Give the postional isomers of 2 halopropane(CH3)2CH

Chemistry

1 answer:

s344n2d4d5 [400]2 years ago

6 0

Give the positional isomers of 2 halopropane

(CH3)2CH

answer:

is in file download it

You might be interested in

How many moles are in 281 g of Ca(OH)2?

Natasha_Volkova [10]

Answer:

3.79 moles

Explanation:

To convert moles to gams of a substance we need to find the molar mass of the substance. For Ca(OH)₂ th molar mass is:

1Ca = 40.08g/mol

2O = 2*16g/mol = 32g/mol

2H = 2*1.01g/mol = 2.02g/mol

The molar mass is:

40.08g/mol + 32g/mol + 2.02g/mol = 74.1g/mol

And moles are:

281g * (1mol / 74.1g) =

<h3>3.79 moles</h3>

5 0

3 years ago

How many moles of KCl are in 28g of KCl?

eduard

Answer:

0.38 moles KCl

Explanation:

(28 g KCl) / (74.55 g/mol KCl) = 0.38 moles KCl

7 0

2 years ago

Read 2 more answers

The solid anhydrous solid CoCl2 is blue in color. Because it readily absorbs water from the air, it is used as a humidity indica

MrRissso [65]

Answer:

$CoCl_{2}.(H_{2}O)_{6}$ is formed and it has three unpaired electrons.

Explanation:

Blue $CoCl_{2}$ reacts with water to produce pink colored $CoCl_{2}.(H_{2}O)_{6}$ complex.

In this complex, $Co^{2+}$ ion forms an octahedral complex with six $H_{2}O$ ligands.

As $H_{2}O$ is a weak field ligand therefore $Co^{2+}$ ion remains in low spin state.

Hence electronic configuration of $Co^{2+}$ ion in this octahedral geometry is $t_{2g}^{5}e_{g}^{2}$ with total three unpaired electrons.

6 0

3 years ago

Convert 15.2 moles of K to atoms of K.

choli [55]

Answer:

$\boxed {\boxed {\sf 9.15*10^{24} \ atoms \ K}}$

Explanation:

To convert atoms to moles, Avogadro's Number must be used: 6.022*10²³.

This tells us the amount of particles (atoms, molecules, etc.) in 1 mole of a substance. In this case it is the atoms of potassium. We can create a ratio.

$\frac {6.022*10^{23} \ atoms \ K }{ 1 \ mol \ K }$

Multiply by the given number of moles: 15.2

$15.2 \ mol \ K *\frac {6.022*10^{23} \ atoms \ K }{ 1 \ mol \ K }$

The moles of potassium cancel.

$15.2 *\frac {6.022*10^{23} \ atoms \ K }{ 1 }$

The denominator of 1 can be ignored.

$15.2 * {6.022*10^{23} \ atoms \ K }{$

Multiply.

$9.15344*10^{24} \ atoms \ K$

The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we calculated that is the hundredth place. The 3 in the thousandth place tells us to leave 5.

$9.15*10^{24} \ atoms \ K$

In 15.2 moles of potassium, there are 9.15*10²⁴ atoms of potassium.

3 0

3 years ago

Write the balanced chemical equation between H2SO4H2SO4 and KOHKOH in aqueous solution. This is called a neutralization reaction

const2013 [10]

Answer:

0.185M sulfuric acid

Explanation:

Based on the reaction:

H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O

1 mole of sulfuric acid reacts with 2 moles of KOH

Initial moles of H₂SO₄ and KOH are:

H₂SO₄: 0.750L ₓ (0.470mol / L) = 0.3525 moles of H₂SO₄

KOH: 0.700L ₓ (0.240mol / L) = 0.168 moles of KOH

The moles of sulfuric acis that react with KOH are:

0.168mol KOH ₓ (1 mole H₂SO₄ / 2 moles KOH) = 0.0840 moles of sulfuric acid.

Thus, moles that remain are:

0.3525moles - 0.0840 moles = 0.2685 moles of sulfuric acid remains

As total volume is 0.700L + 0.750L = 1.450L, concentration is:

0.2685mol / 1.450L = 0.185M sulfuric acid

8 0

3 years ago

Give the postional isomers of 2 halopropane(CH3)2CH​

Give the postional isomers of 2 halopropane(CH3)2CH