Give the postional isomers of 2 halopropane (CH3)2CH

How much heat, in joules, must be added to a 75.0-g iron block with a specific heat of 0.449 J/g °C to increase its temperature

svp [43]

Answer:

50,849.25 Joules

Explanation:

The amount of heat, Q, required to raise the temperature of a body with mass, m, and specific heat capacity, c is given by:

Q = mcΔT, where ΔT represents the change in temperature.

In the case of the iron block:

m = 75 g

c = 0.449 J/g °C

ΔT = 1535 - 25 = 1510 °C

Therefore,

Q = 75 g x 0.449 J/g °C x 1510 °C

= 50,849.25 Joules

Hence, 50,849.25 Joules of heat must be added to a 75.0-g iron block with a specific heat of 0.449 J/g °C to increase its temperature from 25 °C to its melting temperature of 1535 °C

5 0

3 years ago

Pls help me will mark brainliest, chemistry equilibrium!!!

Sergeeva-Olga [200]

Answer:

See attached => LeChatelier's Principle

Explanation:

LeChatelier's Principle => If a stress is applied to a chemical reaction, the reaction chemistry will shift away from the applied stress and establish a new equilibrium having new concentration values different from the original concentration values.

There are three (3) principle stress factors that will cause disturb a chemical reaction and cause it to shift to establish a new equilibrium. These are ...

=> concentration effects,

=> temperature effects, and

=> pressure-volume effects.

The attached notes explain in general terms how to evaluate a chemical reaction under an applied stress factor and determine direction of shift to establish a new equilibrium stability. Compare and apply to the worksheet problems.

_______

Answers to worksheet (compare to attached notes)

1a. => increasing wt to product side => tilts right => shifts left

1b. => removing wt from reactant side => tilts right => shifts left,

1c. => increasing wt to product side => tilts right => shifts left

2a. => tilts left (excess wt from Hg), shifts right,

2b. => Increase pressure shifts toward lower molar gas volume side (right) Note: apply only to gas phase substances, Hg is in liquid phase.

3a. exothermic rxn => cooling => tilts left, rxn shifts right

3b. endothermic rxn => cooling => tilts right, rxn shifts left

3c. exothermic rxn => cooling => tilts left, rxn shifts right

_____________

don't forget => brainliest :-)

3 0

3 years ago

A sample of a substance has a mass of 27.3 grams and a volume of 7.0 centimeters3. The density of this substance is

lora16 [44]

Answer:

The density of the substance is 3.9 grams per cubic centimeter.

Explanation:

Given mass=27.3 grams

volume=7 cubic centimeter

We need to find the density.

Density of a substance can be calculated by dividing mass of substance by volume of a substance

$Density\ =\ \frac{mass}{volume}$

$\\Therefore\ density\ =\ \frac{27.3}{7} \ =\ 3.9\ \frac{gm}{cm^3}$

Hence Density of the substance is $3.9gm/cm^3$ .

4 0

3 years ago

Determine the electron-group arrangement, molecular shape, and ideal bond angle(s) for each of the following:

lubasha [3.4K]

Solution :

a). $SO_3$

This compound is known as sulfur trioxide.

The molecular shape of sulfur trioxide is trigonal planer.

And the bond angle is 120°.

b). $N_2O$

This compound is known as Nitrous oxide. Here, nitrogen is in the center. There is no lone pair around the nitrogen atom and it forms two sigma bonds with the other two atoms.

It is linear in shape.

The bond angle between them is 180°.

c). $CH_2Cl_{2}$

This compound is known as the Dichloromethane.

The molecular shape of the compound is tetrahedral.

The bond angles is 120°

6 0

3 years ago

Why are the alloys harder than pure iron

balu736 [363]

Answer:

ok

Explanation:

Alloys are harder and stronger because the different-sized atoms of the mixed metals make the atomic layers less regular, so they cannot slide as easily.

6 0

3 years ago

Give the postional isomers of 2 halopropane(CH3)2CH​

Give the postional isomers of 2 halopropane(CH3)2CH