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Luba_88 [7]
3 years ago
11

Which compound contains ionic bonds?A. NaBr(s)B. HBr(g)C. CH220 (s)D. CO2(g)​

Chemistry
2 answers:
Mekhanik [1.2K]3 years ago
3 0
NaBr contains ionic bonds
fgiga [73]3 years ago
3 0
I think its A NaBr(s)
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Answer:

45.02 L.

Explanation:  

  • Firstly, we need to calculate the no. of moles of water vapor.
  • n = mass / molar mass = (36.21 g) / (18.0 g/mol) = 2.01 mol.
  • We can calculate the volume of knowing that 1.0 mole of a gas at STP occupies 22.4 L.

<em><u>Using cross multiplication:</u></em>

1.0 mole of CO occupies → 22.4 L.

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∴ The volume of water vapor in 36.21 g = (22.4 L)(2.01 mole) / (1.0 mole) = 45.02 L.

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Answer:

The answer is 74.5%.

Explanation:

As we know that % yield=  \frac{actual yield}{theoretical yield} x 100%.

Therefore,

Step 1 Calculate Theoretical yield:

0.112H_{2} x   \frac{1 mol H_{2} }{2.016 g of H{2} }    x    \frac{4 mol H_{2}O }{4 mol H_{2} }    x  \frac{18.02 g H_{2}O }{1 mol H_{2}O}   = 1.001 g H_{2}O

Now Step 2

% yield   =  \frac{actual yield}{theoretical yield} x 100% =   \frac{0.745g}{1.001g} = 74.5%

8 0
3 years ago
1. How can systems with such different structures perform the same function?
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3 0
2 years ago
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how many electrons does silver have to give up in order to achieve a sido noble gas electron configuration
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Answer:

Silver has to give up one electron.

Explanation:

Silver is a transition element and has a partially filled 4d- orbital having 9 electrons and a 5s orbital having 2 electrons in it. In order to achieve stability, silver must have completely filled d-orbital having a maximum number of 10 electrons in it.

Therefore, one electron from 5s orbital jumps to 4d orbital to make it stable. Now, 5s orbital has only one electron, and it will be easy for silver to lose this electron to attain a stable electronic configuration.

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3 years ago
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