Two technicians are discussing relays. Technician A says that relays can fail because the relay winding is open. Technician B sa
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Answer:
Maximum shear stress= 5.66 ksi
Maximum tensile stress= 5.66 ksi
Maximum compressive stress=-5.66 ksi
Maximum shear strain=0.000943
Maximum tensile strain= 0.0004715
Maximum compressive strain= -0.0004715
Explanation:
For acircular bar, the maximum shear stress will be given by
where d is the diameter and T is torque.
By substituting 30 kip-in for torque and 3 in for d then
Maximum shear stress=
Also, the maximum tensile and compressive stresses will be 5.66 ksi and -5.66 ksi respectively.
The maximum shear strain will be given by stress divided by modulus of elasticity, in this case 6000 G
Maximum shear strain will be
The maximum tensile strain will be the above divided by 2 whereas the maximum compressive strain will be negative of tensile strain hence
Maximum compressive strain will be