Answer:
Relative density = 0.545
Degree of saturation = 24.77%
Explanation:
Data provided in the question:
Water content, w = 5%
Bulk unit weight = 18.0 kN/m³
Void ratio in the densest state, 
= 0.51
Void ratio in the loosest state, 
= 0.87
Now,
Dry density, 
= 17.14 kN/m³
Also,
here, G = Specific gravity = 2.7 for sand
or
e = 0.545
Relative density = 
= 
= 0.902
Also,
Se = wG
here,
S is the degree of saturation
therefore,
S(0.545) = (0.05)()2.7
or
S = 0.2477
or
S = 0.2477 × 100% = 24.77%
Answer: Fiber Optic Network Fiber-optic networks have been used for decades to transmit large volumes of traffic across the country. The economics of fiber networks have only recently allowed for connecting the fiber directly to the home, creating a fiber-to-the-home (FTTH) network.
Explanation:
Answer:
0.2 m/s
Explanation:
The velocity of a point on the edge of a disk rotating disk can be calculated as:
Where 
is the angular velocity and r the radius of the disk. This leads to:
It costs 300
Perimeter = 2(L+B)
2(10+5)
2(15) = 30
10 — 1metre
X — 30metres
30metres = 300
Hope that helps :)
Answer:
Both Tech A and B are correct
Explanation:
One the three method of turning off the MIL is when Vehicle drive on 3 consecutive trips with warm-up cycle without detecting fault. So, with this statement, Tech A is correct.
The MIL will be acrivated when DTC stored in memory and so, the Tech B is also correct.
