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pav-90 [236]
1 year ago
7

A sample of a gas at room temperature occupies a volume of 24.0 L at a pressure of 602 torr . If the pressure changes to 3010 to

rr , with no change in the temperature or moles of gas, what is the new volume, V2
Chemistry
1 answer:
yanalaym [24]1 year ago
8 0

Answer:

V₂ = 4.80 L

Explanation:

Because you are dealing solely with pressure and volume, you can find the new volume using the Boyle's Law equation. The general equation looks like this:

P₁V₁ = P₂V₂

In this form, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the new pressure and volume. You have been given all of the variables but V₂. Therefore, by plugging these values into the equation, you can simplify to find your answer.

P₁ = 602 torr              V₁ = 24.0 L

P₂ = 3010 torr            V₂ = ?

P₁V₁ = P₂V₂                                               <---- Boyle's Law equation

(602 torr)(24.0L) = (3010 torr)V₂             <---- Plug variables into equation

144448 = (3010 torr)V₂                            <---- Multiply 602 and 24.0

4.80 = V₂                                                 <---- Divide both sides by 3010

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