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pav-90 [236]
1 year ago
7

A sample of a gas at room temperature occupies a volume of 24.0 L at a pressure of 602 torr . If the pressure changes to 3010 to

rr , with no change in the temperature or moles of gas, what is the new volume, V2
Chemistry
1 answer:
yanalaym [24]1 year ago
8 0

Answer:

V₂ = 4.80 L

Explanation:

Because you are dealing solely with pressure and volume, you can find the new volume using the Boyle's Law equation. The general equation looks like this:

P₁V₁ = P₂V₂

In this form, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the new pressure and volume. You have been given all of the variables but V₂. Therefore, by plugging these values into the equation, you can simplify to find your answer.

P₁ = 602 torr              V₁ = 24.0 L

P₂ = 3010 torr            V₂ = ?

P₁V₁ = P₂V₂                                               <---- Boyle's Law equation

(602 torr)(24.0L) = (3010 torr)V₂             <---- Plug variables into equation

144448 = (3010 torr)V₂                            <---- Multiply 602 and 24.0

4.80 = V₂                                                 <---- Divide both sides by 3010

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Create a story and describe the motion (in meters) of an object that has traveled a distance but has no displacement. Need Help
vekshin1

Answer:

One complete revolution around a circular path.

Explanation:

Let us take the case of a car moving in a circular track of radius r metres.

In one revolution, the car covers the length(distance) equal to the perimeter of the circle.

In this case, distance traveled = 2\pir metres

But after one complete revolution, the car reaches the same position as it was at the beginning of the motion.

Hence, the initial and final points coincide or the car hasn't changed it's position w.r.t the initial point.

So in this case, the displacement is zero.

Hence, revolution of a car around a circular path is an example of an object traveling a distance but having no displacement.

3 0
3 years ago
The solubility of acetanilide is 12.8 g in 100 mL of ethanol at 0 ∘C, and 46.4 g in 100 mL of ethanol at 60 ∘C. What is the maxi
weqwewe [10]

Answer: 72.41% and 26.90% respectively.

Explanation:

At 60°C, you can dissolve 46.4g of acetanilide in 100mL of ethanol. If you lower the temperature, at 0°C, you can dissolve just 12.8g, which means (46.4g-12.8g)=33.6g of acetanilide must have precipitated from the solution.

We can calculate recovery as:

\%R=\frac{crystalized\ mass}{initial\ mass}*100 =\frac{33.6\ g}{46.4\ g}*100=72.41\%

So the answer to the first question is 72.41%.

For the second part just use the same formula, the mass of the precipitate is the final mass minus the initial mass, (171mg-125mg)=46mg.

\%R=\frac{crystalized\ mass}{initial\ mass}*100 =\frac{46\ mg}{171\ mg}*100=26.90\%

So the answer to the second question is 26.90%.

3 0
2 years ago
The rate constant for the decomposition reaction of H2O2 is 3.66 × 10−3 s−1 at a particular temperature. What is the concentrati
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Answer:  3.72 M

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant = 3.66\times 10^{-3}s^{-1}

t = age of sample = 15.0 minutes

a = let initial amount of the reactant  = 10.0 M

a - x = amount left after decay process = ?

15.0\times 60s=\frac{2.303}{3.66\times 10^{-3}}\log\frac{10.0}{(a-x)}

\log\frac{100}{(a-x)}=1.43

\frac{100}{(a-x)}=26.9

(a-x)=3.72M

The concentration of H_2O_2 in a solution after 15.0 minutes have passed is 3.72 M

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2 years ago
Which of the following liquids would have the highest viscosity at room temperature?
Liono4ka [1.6K]

Answer:

5)HOCH2CH2OH

Explanation:

This is also known as ethylene glycol. An increase in hydrogen bonds of a compound means an increase in the viscosity. Hydrogen bonds occur as a result of bonding with electronegative elements such as Oxygen, Nitrogen etc.

The compounds with the highest amount of Hydrogen bond represents the one with the highest viscosity which is B) HOCH2CH2OH

3 0
3 years ago
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