Answer: polar solvent
Explanation:
Polarity can be said to mean, charge separation. Thus, polar solvents are solvents that have charge separation and the ability to solvate i.e dissolve ions.
A polar solvent molecule has slight electrical charge as a result of its shape. A typical and most common example is water, with an oxygen and two hydrogen atoms. The two hydrogen atoms are at an angle to the single oxygen atom. Water is the classic polar solvent. The oxygen atom tends to polarize electron density to itself.
Answer:
Radius of the interior sphere = 3.847 nm
Explanation:
The volume of the shell (Vs) is equal to the difference of the volume of the outer sphere (Vo) and the volume of the inner sphere (Vi). Then:

If we express the radius of the outer sphere (ro) in function of the radius of the inner sphere (ri), we have (e being the shell thickness):

The first equation becomes

To find ri that satisfies this equation we have to find the roots of the polynomial.
Numerically, it could be calculated that ri=3.847 nm satisfies the equation.
So if the radius of the interior sphere is 3.847 nm, the volume of the interior sphere is equal to the volume of the shell of 1nm.
Answer:
MgCl2 (s) + Li2CO3 (s) ==> MgCO3 (s) + 2LiCl (aq)
Double Replacement
Explanation:
MgCl2 (s) + Li2CO3 (s) ==> MgCO3 (s) + 2LiCl (aq)
Double Replacement
Halogens are Soluble
Carbonates are Insoluble
This reaction DOES take place.
Answer:
30 μmol/L
Explanation:
<em>A chemist prepares a solution of barium chloride by measuring out 8.9 μmol of barium chloride into a 300mL volumetric flask and filling the flask to the mark with water.
</em>
<em>
Calculate the concentration in μmol L of the chemist's barium chloride solution. Round your answer to 2 significant digits.</em>
<em />
The chemist has 8.9 μmol of solute (barium chloride) and he adds water until the mark of 300 mL in the container, which is the volume of the solution. We will need the conversion factor 1 L = 1000 mL. The concentration of barium chloride in μmol/L is:

Answer:
0.8988
Explanation:
To calculate the fractional saturation of hemoglobin , the formula used is
YO_2=
now putting the values
YO_2= 
= 
=0.8988
Therefore, fractional saturation of hemoglobin= 0.8988
where
YO_2= fractional saturation of hemoglobin
pO_2= partial pressure of oxygen
p50= is the pO_2 at which hemoglobin is 50% saturated