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N76 [4]
3 years ago
15

According to Archimedes' principle, the mass of a floating object equals the mass of the fluid displaced by the object. A 150-lb

m swimmer is floating in nearby pool; 95% of her body's volume is in the water while 5% of her body's volume is above water. Determine the density of the swimmer's body The density of water is 0.036 lbm/in5. Does your answer make sense?? Why why not?
Chemistry
1 answer:
julsineya [31]3 years ago
5 0

Answer:

The density of the swimmer is 0.0342 lbm/in3.

This value makes sense as the density of the body is very similar to the water.

Explanation:

If the swimmers is floating, the weight of the swimmer must be equal to the upward buoyant force.

We can express the weight force as the product of density and volume of the swimmer.

Then

\rho_{swimmer}*V_{swimmer}=\rho_{water}*V_{water_displaced}\\\\\rho_{swimmer}*V_{swimmer}=\rho_{water}*0.95**V_{swimmer}\\\\\rho_{swimmer}=0.95*\rho_{water}\\\\\rho_{swimmer}=0.95*0.036 lbm/in3\\\\\rho_{swimmer}=0.0342lbm/in3

It makes sense as the density of the body is very similar to the water.

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What are the relationships between temperature and viscosity of water?
iris [78.8K]

Explanation:

Both cohesion and molecular interchange contribute to liquid viscosity. The impact of increasing the temperature of a liquid is to reduce the cohesive forces while simultaneously increasing the rate of molecular interchange. The former effect causes a decrease in the shear stress while the latter causes it to increase.

temperature?

The viscosity of liquids decreases rapidly with an increase in temperature, and the viscosity of gases increases with an increase in temperature. Thus, upon heating, liquids flow more easily, whereas gases flow more sluggishly.

mark as brainliest

8 0
3 years ago
A. what is the hybridization of the central atom in cse2?
elixir [45]

The orbital hybridization of the central carbon atom in CSe2 is sp.

In chemical bonding, atomic orbitals may be combined to form appropriate hybrid orbitals suitable for bonding. The orbitals that combine during hybridization must be close enough in energy.

In the compound Cse2, carbon is the central atom bonded to two selenium atoms. The carbon atom in CSe2 is sp hybridized.

Learn more about orbital hybridization:  brainly.com/question/1869903

4 0
2 years ago
If you refuse a legal chemical test issued by a law enforcement officer, the Division of Motor Vehicles is required to:
Andru [333]

Answer: Revoke the driver's license for at least 12 months

Explanation:

Chemical tests are used in order to measure the amount of drugs or alcohol that is in the body of a person when the person was arrested. To do this, samples of the urine or blood of the person can be taken and the result will be used to know if the person was driving under the influence of alcohol or not.

If the person refuse a legal chemical test issued by a law enforcement officer, the Division of Motor Vehicles is required to revoke the the driver's license of the person for at least 12 months.

6 0
2 years ago
A generic weak acid with formula HA has a Ka = 2.76 x 10-8. Calculate the Kb for the conjugate base of the acid.
Reika [66]

Answer:

3.62x10⁻⁷ = Kb

Explanation:

The acid equilibrium of a weak acid, HX, is:

HX + H₂O ⇄ X⁻ + H₃O⁺

Where Ka = [X⁻] [H₃O⁺] / [HX]

And basic equilibrium of the conjugate base, is:

X⁻ + H₂O ⇄ OH⁻ + HX

Where Kb = [OH⁻] [HX] / [X⁻]

To convert Ka to Kb we must use water equilibrium:

2H₂O ⇄ H₃O⁺ + OH⁻

Where Kw = 1x10⁻¹⁴ = [OH⁻] [H₃O⁺]

Thus, we can obtain:

Kw = Ka*Kb

Solving for Kb:

Kw / Ka = Kb

1x10⁻¹⁴ /  2.76x10⁻⁸ =

3.62x10⁻⁷ = Kb

4 0
3 years ago
An analysis of a sugar compound is found to contain 132 grams of carbon (C), 22 grams of hydrogen (H), and 176 grams of oxygen (
ddd [48]
132 g of C  ,   22 g of H   , 176 g of O

132 + 22 + 176 => 330 g <span>of the substance

</span>Now convert the masses in <span>moles :
</span>
C = 12.0 u        H = 1.0 u       O = 16.0 u

C = 132 / 12.0 => 11 moles

H = 22 / 1.0 => 22 moles

O = 176 / 16.0 => 11 moles

Using the values obtained the lowest proportion in mols of elements present, simply divide the values found for the least of them<span>:
</span>
C = 11 / 11 => 1

H = 22 / 11 => 2

O = 11 / 11 => 1

 formula empirically <span>is : CH</span>₂O

hope this helps!


8 0
3 years ago
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