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gtnhenbr [62]
2 years ago
7

Keenan places 3 green marbles, 4 yellow marbles and 1 blue marble in a bag.

Mathematics
2 answers:
Lady_Fox [76]2 years ago
5 0

Answer:

Stayed the same

Step-by-step explanation:

Altogether, there are 8 marbles in the bag (before Keenan adds the other marbles.) The probability so far that he draws a yellow marble is 4/8, or 1/2.

When he adds the marbles to the bag, there are 10 marbles altogether and 5 yellow marbles. The probability now is 5/10, or 1/2.

The probability has stayed the same.

WINSTONCH [101]2 years ago
3 0

Answer:

Step-by-step explanation:

Beginning

Beginning total = 3 + 4 + 1 = 8

Beginning probability 4/8 = 1/2

<em>Answer: So P(yellow) = 1/2</em>

New Conditions

4 + 5 + 1 = 10

P(y) = 5/10 = 1/2

<em>Answer: Stays the same</em>

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Work out the equation of the line which has a gradient of -2 and passes through the point (4, 8).​
max2010maxim [7]

Answer:

y = -2x + 16.

Step-by-step explanation:

We are given the slope and a point on the line, so

we use the point-slope form of a straight line:

y - y1 = m(x - x1)

Here gradient m = -2, x1 = 4 and y1 = 8 , so we have:

y - 8 = -2(x - 4)

y - 8 = -2x + 8

y = -2x + 16.

3 0
2 years ago
Read 2 more answers
Find the value of KL.<br> KL= 3x + 2 and LM= 5x - 10
Mariana [72]

From the given graph, we can tell kl=lm 

therefore,

3x + 2 = 5x - 10

3x+2-2=5x-10-2 

subtract 2 from both sides. 

3x+ 0 =5x-12 3x=5x-12 

3x-5x=5x-5x-12 

subtract 5x from both sides.

-2x=0-12 -2x=-12 (-2x)/-2=-12/-2 

divide both sides by -2. 

1x= 6 -12/-2=6 

and of course the -2 and -2 cancel on left side leaving 1x. 

x=6

KL = 3x+2 = 20 units

7 0
4 years ago
If cot theta = -2, find the value of cot theta + cot (theta -pi) + cot (theta-2pi)
nika2105 [10]

Given:

\cot \theta = -2

To find:

The value of \cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi).

Solution:

We know that,

\cot (\theta -n\pi)=\cot \theta         ...(i)

Where n is an integer.

We have,

\cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi)

Using (i), it can be written as

\cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi)=\cot \theta +\cot \theta +\cot \theta

\cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi)=3\cot \theta

It is given that \cot \theta = -2.

\cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi)=3(-2)

\cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi)=-6

Therefore, the value of the given function expression is -6.

6 0
3 years ago
In an investigation of pregnancy-induced hypertension, one group of women with this disorder was treated with low-dose aspirin,
AleksandrR [38]

Answer:

Step-by-step explanation:

Given that in an investigation of pregnancy-induced hypertension, one group of women with this disorder was treated with low-dose aspirin, and a second group was given a placebo. A sample consisting of 50 women who received aspirin has mean arterial blood pressure 120mmHg and standard deviation 10mmHg; a sample of 42 women who were given the placebo has mean blood pressure 115mmHg and standard deviation 12mmHg.

Population variances are equal

H_0: \bar x = \bar y\\H_a: \bar x \neq \bar y

(two tailed test at 5% significance level)

Here x denotes group I and Y group II

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Sample 1   50     120      10  1.4142

Sample 2 42       115      12  1.8516

Pooled std deviation = 10.9565

df=80

Mean difference= 5

Test statistic t = mean diff/std error = \frac{5}{2.3299}=2.1803

p value = 0.0318

since p <0.05 we reject H0

b) We find p >0.01 hence at 1% significance level we accept H0

This implies that 99% confidence interval contains mean difference =0

4 0
4 years ago
Today Jason has 123 stamps in his collection. He got 5 stamps at a show last week. Then he got 4 more stamps at a show this week
lozanna [386]
114 stamps he had before
3 0
4 years ago
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