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Damm [24]
3 years ago
12

If cot theta = -2, find the value of cot theta + cot (theta -pi) + cot (theta-2pi)

Mathematics
1 answer:
nika2105 [10]3 years ago
6 0

Given:

\cot \theta = -2

To find:

The value of \cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi).

Solution:

We know that,

\cot (\theta -n\pi)=\cot \theta         ...(i)

Where n is an integer.

We have,

\cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi)

Using (i), it can be written as

\cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi)=\cot \theta +\cot \theta +\cot \theta

\cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi)=3\cot \theta

It is given that \cot \theta = -2.

\cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi)=3(-2)

\cot \theta +\cot (\theta -\pi)+\cot(\theta -2\pi)=-6

Therefore, the value of the given function expression is -6.

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<u><em>The complete question is</em></u>

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