So basically you will have to label the purple parent 1 and whatever gene that is then the same for parent 2 here is an example of a punnet square so maybe you can understand better
The act of avoiding an immediately enjoyable behavior in the hopes of getting an even better reward at a later time.
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Parents: Homozygous brown-eyed (M) - B B
blued-eye (F) - b b [since blue (b) is recessive then and brown (B) is dominant then
in order for the blue gene to
show the you need double recessive or the brown
gene absent
Offspring:
So based on the Punnett cross then you realize that all the possible of spring carry the genotype B b and as such the phenotype brown eyes
blued-eye (F) - b b [since blue (b) is recessive then and brown (B) is dominant then
in order for the blue gene to
show the you need double recessive or the brown
gene absent
Offspring:
So based on the Punnett cross then you realize that all the possible of spring carry the genotype B b and as such the phenotype brown eyes