In order to do this, you must first find the "cross product" of these vectors. To do that, we can use several methods. To simplify this first, I suggest you compute:
‹1, -1, 1› × ‹0, 1, 1›
You are interested in vectors orthogonal to the originals, which don't change when you scale them. Using 0,-1,1 is much easier than 6s and 7s.
So what methods are there to compute this? You can review them here (or presumably in your class notes or textbook):
http://en.wikipedia.org/wiki/Cross_produ...
In addition to these methods, sometimes I like to set up:
‹1, -1, 1› • ‹a, b, c› = 0
‹0, 1, 1› • ‹a, b, c› = 0
That is the dot product, and having these dot products equal zero guarantees orthogonality. You can convert that to:
a - b + c = 0
b + c = 0
This is two equations, three unknowns, so you can solve it with one free parameter:
b = -c
a = c - b = -2c
The computation, regardless of method, yields:
‹1, -1, 1› × ‹0, 1, 1› = ‹-2, -1, 1›
The above method, solving equations, works because you'd just plug in c=1 to obtain this solution. However, it is not a unit vector. There will always be two unit vectors (if you find one, then its negative will be the other of course). To find the unit vector, we need to find the magnitude of our vector:
|| ‹-2, -1, 1› || = √( (-2)² + (-1)² + (1)² ) = √( 4 + 1 + 1 ) = √6
Then we divide that vector by its magnitude to yield one solution:
‹ -2/√6 , -1/√6 , 1/√6 ›
And take the negative for the other:
‹ 2/√6 , 1/√6 , -1/√6 ›
The value of log subscript 6 baseline start fraction 1 over 36 end fraction is -2.
Let x is the unknown value
We have to determine the value of x
<h3>What is the meaning of logarithmic function?</h3>
Logarithmic functions are the inverses of exponential functions, and an exponential function can be expressed in logarithmic form.
We know that,
Therefore by applying the above rule of log we have
Therefore we get
Therefore option 2 is correct.
To learn more about the logarithmic expression visit:
brainly.com/question/1832186
A es la respuesta correcta. Hay tantas monedas en un banco, que es imposible contarlas todas. Disculpe mi pobre español, lo siento. :)
Answer:
The fraction of male student who play sport is 
Step-by-step explanation:
Given as :
Out of the total number of students , the fraction of male = 
of total number of students
Let the total number of students = x
So, The fraction of male student = of x
I.e The fraction of male student = 
Again
The number of students who play sports = 
of total number of students
Or, The number of students who play sports = of x
Or, The number of students who play sports = 
Let The total number of male student who play sport = y
So, According to question
of y =
I.e × y =
or, y = 
∴ y =
So, The total number of male student who play sport = y =
Hence ,The fraction of male student who play sport is Answer
