How many intergers between 5 and 2b

1 answer:

4 0

As a proof of concept, calculate the number of integers that fall between 5 and 10 on a number line. We know there are 4 (6, 7, 8, 9).

Missing: 2b ‎| Must include: 2b

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Solve equation 5b - (5b -

tester [92]

Hello I believe your answer is going to be 2 I assumed the b's were x's

4 0

3 years ago

Santana wants to give one-thenths of all his marbles plus eight to his brother. Which expression can Santana use to calculate ho

Schach [20]

For this case we have the following variable:
m = Santana's total marbles
We must write an expression as a function of m to model the problem.
"Santana wants to give one-thenths of all his marbles plus eight to his brother"
The function is:
f (m) = (1/10) m + 8
Answer:
An expression that Santana can use is:
f (m) = (1/10) m + 8

8 0

3 years ago

Please help:(((

Nana76 [90]

Answer: $(x+3)^2=-4(y-3)$

Step-by-step explanation:

From the figure, it is downward parabola of the form $x^2=-4ay$

The parabola has its vertex at $(-3,3)$

Distance between parabola vertex and its directrix is 1 unit.

So, the value of a is 1

Hence, the equation of parabola is $(x+3)^2=-4(y-3)$

7 0

3 years ago

The area of the region in the first quadrant between the graph of y = k*sin(x) and x-axis (where k > 0 ) on the closed interv

astraxan [27]

Note that $0\le k\sin x\le k$ in the given closed interval, so the area is exactly given by the definite integral

$\displaystyle\int_0^\pi k\sin x\,\mathrm dx$

(no absolute values needed!)

Integrating gives

$-k\cos x\bigg|_{x=0}^{x=\pi}=-k(\cos\pi-\cos0)=-k(-1-1)=2k$

8 0

4 years ago

The length of a rectangle is 9.7 cm more than 4 times the width. if the perimeter of the rectangle is 68.4 cm, what are its dime

aleksklad [387]

P = 2(L + W)
P = 68.4
L = 4W + 9.7

68.4 = 2(4W + 9.7 + W)
68.4 = 2(5W + 9.7)
68.4 = 10W + 19.4
68.4 - 19.4 = 10W
49 = 10W
49/10 = W
4.9 = W <==== the width is 4.9 cm

L = 4W + 9.7
L = 4(4.9) + 9.7
L = 19.6 + 9.7
L = 29.3 <=== the length is 29.3 cm

7 0

4 years ago

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