Answer:
Okapi 290 kg
Llama 160 kg
Step-by-step explanation:
Let weight of each llama be 
Let weight of each okapi be 
<em>Given, combined weight of 1 okapi and 1 llama is 450, we can write:</em>
<em>
</em>
<em>Also, average weight of 3 llama is 190 more than the average weight of 1 okapi, thus we can write:</em>
<em>
</em>
Now, substituting 2nd equation into 1st equation, we can solve for weight of 1 llama:

Each llama weights 160 kg, now using this and plugging into 2nd equation, we get weight of 1 okapi to be:

Each okapi weigh 290 kg
the answer is C, because you solve 2.815-749, and after you divide the result per 4, so it is 1/4
Answer:
A.(-2, 0)
C. (-1.4)
Step-by-step explanation:
we know that
If a point lie on the line, then the point must satisfy the equation of the line (makes the equation true)
we have

subtract 7 both sides


divide by 2 both sides

Substitute the value of x and the value of y of each point in the linear equation and analyze the result
<u><em>Verify each point</em></u>
case A) we have
(-2, 0)
For x=-2, y=0
substitute

---> is true
so
the point lie on the line
case B) we have
(1, 3)
For x=1, y=3
substitute

---> is not true
so
the point not lie on the line
case C) we have
(-1, 4)
For x=-1, y=4
substitute

---> is true
so
the point lie on the line
case D) we have
(1, -4)
For x=1, y=-4
substitute

---> is not true
so
the point not lie on the line
case E) we have
(0, -1)
For x=0, y=-1
substitute

---> is not true
so
the point not lie on the line
Answer:i tihnk football is .45 and tennis is .18?
Step-by-step explanation:
i dont know if this is right but im pretty sure it is
Formula for the area of a triangle:
( Base X Height ) Divided by 2 or (B×H) ÷ 2
Formula for the area of a circle:
PI times the radius squared or PI × r^2
Area of the triangule part of this figure:
Base: 8ft. Height: 6ft
(8ft × 6ft) ÷ 2
48ft^2 ÷ 2
24ft^2
Since the circular part of the figure is a SEMICIRCLE, we are finding the area of a circle with the same radius but dividing it by 2 since thats just a half of a circle
Area of the semicricle:
Diameter: 10ft,
Therefore the radius is 5ft
(PI x 5ft^2) ÷ 2
39.2699081699 ft^2
39.27 ft^2
Now add these two areas together:
24ft^2 + 38.27ft^2 = 62.27ft^2
Hope it helps