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3 years ago

13

Does anyone know the answer? It’s due in an hour PLEASE HELPPP!!

1 answer:

valentinak56 [21]3 years ago

4 0

When i did that sort of thing i had a trick. But you are correct.

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A positive integer is twice another.the sum of the reciprocal of the two positive integer is 3/14. Find the integers

icang [17]

Answer:

$\huge\boxed{14\ \text{and}\ 7}$

Step-by-step explanation:

$n,\ m-\text{positive integer}\\\\n=2m-\text{a positive integer is twice another}\\\\\dfrac{1}{n}+\dfrac{1}{m}=\dfrac{3}{14}-\text{the sum of the reciprocal of the two positive integer is }\ \dfrac{3}{14}\\\\\text{We have the system of equations:}\\\\\left\{\begin{array}{ccc}n=2m&(1)\\\dfrac{1}{n}+\dfrac{1}{m}=\dfrac{3}{14}&(2)\end{array}\right$

$\text{Substitute (1) to (2):}\\\\\dfrac{1}{2m}+\dfrac{1}{m}=\dfrac{3}{14}\\\\\dfrac{1}{2m}+\dfrac{1\cdot2}{m\cdot2}=\dfrac{3}{14}\\\\\dfrac{1}{2m}+\dfrac{2}{2m}=\dfrac{3}{14}\\\\\dfrac{1+2}{2m}=\dfrac{3}{14}\\\\\dfrac{3}{2m}=\dfrac{3}{14}\Rightarrow2m=14\qquad\text{divide both sides by 2}\\\\\dfrac{2m}{2}=\dfrac{14}{2}\\\\\boxed{m=7}$

$\text{Substitute it to (1):}\\\\n=2\cdot7\\\\\boxed{n=14}$

8 0

3 years ago

What goes into 240??

WINSTONCH [101]

1,2,3,4,5,6,8,10,12,15,16,20,24,30,40,48,60,80,120,240

6 0

3 years ago

Solve : (6a -5b -8c) - ( 15b + 2a - 5c)<br><br>

Allushta [10]

Answer:

4a - 20b - 3c

Step-by-step explanation:

6a - 5b - 8c - 15b - 2a + 5c

= 4a - 20b - 3c

5 0

3 years ago

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Daniel has 20 quarts of water. How many 2-quart<br> containers can he fill<br> Show your work

PtichkaEL [24]

Since each container can have 2 quarts, we can divide 20 quarts by 2 quarts per container to get total containers. 20/2=10 separate containers

5 0

4 years ago

Find the area of a regular pentagon with apothem length of about 10.3 meters. Round to the nearest tenth if necessary.

matrenka [14]

Answer:

The area = 182.52 sq units.

Step-by-step explanation:

Area of regular polygon can be found by splitting into smaller triangles.
Each triangle has base as side of polygon and vertex as center of polygon.

now consider ΔOAB,

we know ∠AOB = $\frac{360}{5}$ ° =72°

<h3> (this is due to symmetry)</h3>

as ∠AOD = (∠AOB)/2 = 36°

Now we know AD=AB/2 = $\frac{10.3}{2}$ =5.15 m

using trignometric relation tan(∠AOD) = $\frac{AD}{OD}$

⇒OD = $\frac{AD}{tan(36)}$ = $\frac{5.15}{tan(36)}$

AREA OF TRIANGLE = BASE × HEIGHT /2

area of ΔOAD = $\frac{1}{2}$ × 5.15 × $\frac{5.15}{tan(36)}$

= $\frac{(5.15)^2}{2tan(36)}$

<u>As there are 10 such triangles like </u>ΔOAD

Total area =10× $\frac{(5.15)^2}{2tan(36)}$

= 182.525447428574

4 0

3 years ago

Read 2 more answers