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WITCHER [35]
2 years ago
5

Given the balanced equation representing a

Chemistry
1 answer:
fredd [130]2 years ago
5 0

From the coefficients of the equation, we see that for every 4 moles of aluminum consumed, 3 moles of oxygen are consumed.

So, the answer is (12/4)(3) = 9 moles.

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A sample of a substance has a mass of 4.2 grams and a volume of 6 milliliters
allsm [11]

Answer:

Density of the substance is 0.7

Explanation:

4.2/6 = 0.7

6 0
3 years ago
Read 2 more answers
Rank the following carboxylic acids from strongest (1) to weakest (4)
Paha777 [63]

Answer:

CH2FCOOH > CH2ClCOOH > CH2BrCOOH > CH3COOH

Explanation:

CH2FCOOH > CH2ClCOOH > CH2BrCOOH > CH3COOH

More electronegative atom of halogen is , stronger acid will be.

6 0
3 years ago
Value 1: 45.58g
Rama09 [41]

Answer:

<h2>Percentage error is a measurement of the discrepancy between an observed and a true, or accepted value .</h2>

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7 0
3 years ago
I am having some trouble figuring out how to approach the following problem: A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5) is ti
Tanya [424]
<span>We look at the end of the day:

n(HNO3) added = 0.500*17.0/1000 = 0.00850 mol
n(NH3) = 0.200*75.0/1000 - 0.00850 = 0.00650 mol
[NH3] left = 0.00650*1000/(17.0+75.0) = 0.070652
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4 0
3 years ago
If you burn 29.4 g of hydrogen and produce 263 g of water, how much oxygen reacted?
vovikov84 [41]

The reaction between hydrogen and oxygen to form water is given as:

H_2 + O_2 \rightarrow H_2O

The balanced reaction is:

2H_2 + O_2 \rightarrow 2H_2O

According to the balanced reaction,

4 g of hydrogen (4\times 1) reacts with 32 g of oxygen (2\times 16).

So, oxygen reacted with 29.4 g of hydrogen is:

\frac{29.4\times 32}{4} = 235.2 g

Hence, the mass of oxygen that is reacted with 29.4 g of hydrogen is 235.2 g.

7 0
3 years ago
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