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tamaranim1 [39]
3 years ago
7

Name the molecule when potassium reacts with chlorine?

Chemistry
1 answer:
Dominik [7]3 years ago
4 0

Answer: Potassium Chloride

Explanation:

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In order to heat a round bottom flask in a heating mantle, plug the heating mantle into _______.Turn the heat up _________, and
KATRIN_1 [288]

Answer:

A Variac or Powermite; gradually; 50-60%.

Explanation:

A chemical reaction can be defined as a chemical process which typically involves the transformation or rearrangement of the atomic, ionic or molecular structure of an element through the breakdown and formation of chemical bonds to produce a new compound or substance.

Some of the laboratory apparatus (equipment) used for conducting a chemical reaction are conical flask, Bunsen burner, beaker, tongs, crucible, round bottom flask etc.

In order to heat a round bottom flask in a heating mantle, plug the heating mantle into a Variac or Powermite which is typically used for controlling the level of temperature. Turn the heat up gradually, and do not exceed 50-60% of the maximum output of the device, so as to avoid any electrical issues such as overloading, short-circuit etc.

The safety precautions that must be taken when using a round bottom flask are;

I. A proper inspection of the round bottom flask for cracks, irregularities or any imperfection.

II. Ensure you avoid heating the flask while it is closed.

III. When suspending the round bottom flask on a stand, you should ensure that you use a clamp for stability.

5 0
3 years ago
If there is 30 grams of O2 how many grams of CO2 can it make
igomit [66]

Explanation:

hope it helps you with the question

7 0
3 years ago
Calculate the volume of 5.00 mol of helium at 120C and 1520 mm Hg
levacccp [35]

Answer:

80.7 L

Step-by-step explanation:

This looks like a case where we can use the Ideal Gas Law to calculate the volume.

pV = nRT       Divide both sides by p

V = (nRT)/p

=====

Data:

n = 5.00 mol

R = 0.082 06 L·atm·K⁻¹mol⁻¹

T = (120 +273.15) K = 393.15K

p = 1520 mmHg × 1 atm/760 mmHg = 2.00 atm

=====

Calculation:

V = (5.00 × 0.082 06 × 393.15)/2.00

V = 161.3/2.00

V = 80.7 L  

4 0
3 years ago
Hardness in groundwater is due to the presence of metal ions, primarily Mg2 and Ca2 . Hardness is generally reported as ppm CaCO
Maslowich

Answer:

  • 0.0144 M
  • 1440 ppm

Explanation:

Ca(In)²⁺ + EDTA → Ca(EDTA)²⁺ + In

We use the volume of EDTA consumed in the titration to <u>calculate the moles of Ca⁺² ions</u>:

  • 0.012 L * 0.0600 M * \frac{1molCa^{+2}}{1molEDTA} = 7.20x10⁻⁴ mol Ca⁺²

Now we <u>calculate the molarity</u>:

  • 7.20x10⁻⁴ mol Ca⁺² / 0.050 L = 0.0144 M

To calculate in ppm, we <u>use the moles of Ca⁺² and convert to mg of CaCO₃:</u>

  • 7.20x10⁻⁴ mol Ca⁺² = 7.20x10⁻⁴ mol CaCO₃
  • 7.20x10⁻⁴ mol CaCO₃ * 100g/mol * \frac{1000mg}{1g} = 72 mg CaCO₃

Finally, <u>the concentration in ppm</u> is:

  • 72 mg CaCO₃ / 0.050L = 1440 ppm
5 0
2 years ago
if 334.6 g of phosphoric acid is reacted with excess potassium hydroxide. the final mass K3PO4 produced is found to be 248g. wha
Orlov [11]

Answer:

                     %age Yield  =  34.21 %

Explanation:

                   The balance chemical equation for the decomposition of KClO₃ is as follow;

                            3 KOH + H₃PO₄ → K₃PO₄ + 3 H₂O

Step 1: Calculate moles of H₃PO₄ as;

Moles = Mass / M/Mass

Moles = 334.6 g / 97.99 g/mol

Moles = 3.414 moles

Step 2: Find moles of K₃PO₄ as;

According to equation,

                 1 moles of H₃PO₄ produces  =  1 moles of K₃PO₄

So,

              3.414 moles of H₃PO₄ will produce  =  X moles of K₃PO₄

Solving for X,

                      X = 1 mol × 3.414 mol / 1 mol

                      X = 3.414 mol of K₃PO₄

Step 3: Calculate Theoretical yield of K₃PO₄ as,

Mass = Moles × M.Mass

Mass = 3.414 mol × 212.26 g/mol

Mass = 724.79 g of K₃PO₄

Also,

%age Yield  =  Actual Yield / Theoretical Yield × 100

%age Yield  =  248 g / 724.79 × 100

%age Yield  =  34.21 %

3 0
3 years ago
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