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yan [13]
3 years ago
13

Everyone open this please!

Physics
2 answers:
Tamiku [17]3 years ago
8 0

Answer:

I sit by myself talking to the MOOOOOOOOONNNNNNNN

Explanation:

notsponge [240]3 years ago
7 0

Answer:

yeah i knowwwwwwwwwwwwww

Explanation:

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A gymnast of mass 63.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume t
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Answer:

Explanation:

A ) When gymnast is motionless , he is in equilibrium

T = mg

= 63 x 9.81

= 618.03 N

B )

When gymnast climbs up at a constant rate , he is still in equilibrium ie net force acting on it is zero as acceleration is zero.

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= 618.03 N

C ) If the gymnast climbs up the rope with an upward acceleration of magnitude 0.600 m/s2

Net force on it = T - mg   , acting in upward direction

T - mg = m a

T =  mg + m a

= m ( g + a )

= 63 ( 9.81 + .6)

= 655.83 N

D )  If the gymnast slides down the rope with a downward acceleration of magnitude 0.600 m/s2

Net force acting in downward direction

mg - T = ma

T = m ( g - a )

= 63 x ( 9.81 - .6 )

= 580.23 N

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How do i solve?<br><br>a = bc<br>(b)​
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