Answer:
what is the image in question
Answer:
true b and c
Explanation:
n the electromechanical transitions of the atoms the relationship must be fulfilled
= R (1 / nf - 1 / no²)
where for the final state nf = 1 giving in the case of hydrogen the Lymma series whose smallest wavelength is lam = 122 nm with nf = 1 and there are a series of spectral lines for each value of n of the final state
in the case of sodium so well it has a transition from an excited state to the kiss state (bad)
Now let's review the different proposals
a) False. The electronic potential for sodium is much lower than for hydrognosia
b) True
c) True
d) true
Answer:
The correct option is;
Sphere I is positively charged and sphere II is negatively charged
Explanation:
The charging of the spheres by induction is achieved by introducing a charge to the metal spheres that are insulated from the ground to prevent loss of charge by placing them on insulating stand
The two spheres are brought into contact by the connection of a conducting wire between the spheres I and II
The presence of the positively charged sphere III draws attracts electrons towards sphere II while the net positive charge moves towards sphere I
While the spheres I and II are still polarized, the conducting wire is removed while the presence of sphere III continues to keep sphere II negative compared to sphere I
After removing the connecting wire, sphere III is removed leaving the excess negative charge on sphere II and the excess positive charge on sphere I
The net charges then evenly redistribute themselves on each sphere creating two oppositely charged spheres.
We can use the ideal gas equation which is expressed as PV = nRT. At a constant volume and number of moles of the gas the ratio of T and P is equal to some constant. At another set of condition, the constant is still the same. Calculations are as follows:
T1/P1 = T2/P2
P2 = T2 x P1 / T1
P2 = 273 x 340 / 713
<span>P2 = 130 kPa</span>
Answer:
1 my brother say that
Explanation:
i know my brother said it
