Answer:
= 3.8 m/s
Explanation:
When the runner start the running, she is at rest. So the initial velocity of the runner is zero (0 m/s). And then she accelerates at a rate of 1.9 m/s² for 2.2 s. But we need to find the final velocity after t = 2 s when she starts the running. So, we take time equal to 2 second.
Given data:
Initial velocity =
= 0 m/s
Acceleration = a = 1.9 m/s² (for 2.2 s after starting the race)
Time = t = 2 s
Final velocity =
= ?
According to the First equation of motion
=
+ at
= 0 + (1.9)(2)
= 3.8 m/s
k = 1/2 × m × v^2
_____________________________
1. k = 1/2 × 60 × ( 10 )^2
k = 30 × 100
k = 3000 j
_____________________________
2. k = 1/2 × 60 × ( 9 )^2
k = 30 × 81
k = 2430 j
_____________________________
3. k = 1/2 × 60 × ( 4 )^2
k = 30 × 16
k = 480 j
_____________________________
4. k = 1/2 × 60 × ( 6 )^2
k = 30 × 36
k = 1080 j
______________________________
5. k = 1/2 × 60 × ( 0 ) ^2
k = 30 × 0
k = 0 j
part 1
mass = ρ x V
mass = 1739 kg/m³ x 3.8 km³ = 6608.2 kg
PE (potential energy)= mgh
PE = 6608.2 kg x 9.81 x 403
PE = 2.61 x 10⁷ J
part 2
megaton of TNT (Mt) =4.2 x 10¹⁵ J
convert PE to Mt:
2.61 x 10⁷ J : 4.2 x 10¹⁵ J = 6.21 x 10⁻⁹ Mt
Answer:
Explanation:
= v/f
^That is the formula we are going to use.
Now, we were given the speed (v), which is 20.
Now we need to find frequency, in order to solve for the wavelength.
Frequency is the amount of waves in a fixed unit of one second, meaning our F value is the value of 5 divided by 4.
5/4 = 1.25
Therefore our F is 1.25
Now lets plug it in
= v/f
= 20/1.25
= 16
Conversion:
= 8
Answer:
Explanation:
4/1=4
3/2=1.5
2/3=0.666667
1/4=0.25
D has the least number so its D