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1 year ago

Question 3 of 10 Subtract these polynomials. (6x²-x+ 8) - (x² + 2) =

Mathematics

1 answer:

Julli [10]1 year ago

5 0

Answer:

$5 {x}^{2} - x + 6$

Step-by-step explanation:

The solution is in the image

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Simplify -3d^8(-4d^-14). Assume d =/ 0

Alenkinab [10]

Answer:

$\frac{12}{d^6}$

Step-by-step explanation:

$-3d^8\left(-4d^{-14}\right)$

Double negative = Positive:

$3d^8*4d^{-14}$

Apply negative exponent formula:

$3*d^8*4*\frac{1}{d^{14}}$

Multiply:

$\frac{12d^8}{d^{14}}$

Apply exponent rule: $\frac{x^a}{x^b}=\frac{1}{x^{b-a}}$

Thus, $\frac{12}{d^{14-8}}$

Simplify:

$\frac{12}{d^6}$

8 0

2 years ago

What are the domain and range of the function f(x)=5^x-3+1

Hunter-Best [27]

The domain is the set of all possible values of independent variable I.e of x. The range is the complete set of all possible resulting values of the dependent variable of i.e of y

8 0

3 years ago

Read 2 more answers

Write an equation in standard form of the hyperbola described.

marishachu [46]

Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.

$\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill$

$\begin{cases} h=0\\ k=0\\ a=2\\ c=4 \end{cases}\implies \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{b^2} \\\\\\ c^2=a^2+b^2\implies 4^2=2^2+b^2\implies 16=4+b^2\implies \underline{12=b^2} \\\\\\ \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{12}\implies \boxed{\cfrac{x^2}{4}-\cfrac{y^2}{12}}$

5 0

1 year ago

Which name correctly classifies this triangle? A. right B. obtuse C. acute

sergejj [24]

Hello there!

The would be a (right angle) because this angle is not greater than, or less than 90°.

Your correct answer would be the first option. (right angle).

7 0

2 years ago

The cost of coffee is determined by the type of coffee beans that are mixed together. The cost of a local mix of Arabica and Rob

Sati [7]

Substituting 1000 for A, we have 1200R+700,000=1,000,000. Subtracting 700,000 from both sides, we have 1200R=300,000. Dividing by 1200, we see that R=250.

7 0

2 years ago