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2 years ago

What is the congruence correspondence, if any, that will prove the given triangles congruent?

Mathematics

1 answer:

MakcuM [25]2 years ago

7 0

Answer: C : SAS

Explanation:
S = Side
A = Angle

They both follow the same correspondence SAS.

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Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.

Tasya [4]

Answer:

$\frac{dy}{dx}=-[(\frac{5x+24}{36x-6x^2})]$

Step-by-step explanation:

Given function:

y = $\ln(\frac{(6 - x)^{\frac{3}{2}}}{x^{\frac{2}{3}}})$

we know

$\ln(\frac{A}{B})$ = ln(A) - ln(B)

thus,

y = $\ln((6 - x)^{\frac{3}{2}}) - \ln(x^{\frac{2}{3}})$

also,

ln(Aⁿ) = n × ln(A)

thus,

y = $(\frac{3}{2})\times\ln(6 - x) - (\frac{2}{3})\times\ln(x)$

therefore,

$\frac{dy}{dx}=[(\frac{3}{2})\times\frac{1}{(6-x)}\times(0 - 1)] - [ (\frac{2}{3})\times\frac{1}{x}\times1]$

$\frac{dy}{dx}=-(\frac{3}{2(6-x)}) - (\frac{2}{3x})$

$\frac{dy}{dx}=-[(\frac{3(3x)+2\times2(6-x)}{2(6-x)\times(3x)})]$

$\frac{dy}{dx}=-[(\frac{5x+24}{36x-6x^2})]$

5 0

3 years ago

A holiday costs £1200. Work out the price after a 7% discount.

vfiekz [6]

Answer:

1116

Step-by-step explanation:

0.93(1200)

1116

8 0

3 years ago

At the Souvenir Shop, gemstone souvenirs cost $11.60 for 5. Which proportion can be used to find the cost of just 1 gemstone?

Natasha2012 [34]

Answer:

see below

Step-by-step explanation:

$11.60 for $5

1. Find the rate.

$11.60 divided by $5= $2.32

2. 1 gemstone= $2.32

Your anwser should be 1 over $2.32 or $2.32 over 1 depending on how you want it.

5 0

3 years ago

Please help me with this problem im having trouble answering this

adell [148]

Answer:

tgtftgrfrfrdrxdrdrcrcrcrxrxrxrc

4 0

3 years ago

The formula Y=X⁴-4X³+3X² is growing?

miskamm [114]

Answer:

The best way to know weather the formula y=x⁴-4x³+3x² is growing or not, is by graphing it.

As you can see in the attached picture:

For -inf<x< 0 the graph decreases.
For 0<x<0.634 the graph is growing
For 0,634<x<2.366 the graph decreases
For 2.366<x<+inf the graph is growing.

Therefore, the polynomial grows in the intervals stated before.

6 0

3 years ago