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tatuchka [14]
3 years ago
8

There are 176 gallons of gas in tank a. There are 19 gallons less gas in tank b. How many gallons of gas are there in take b

Mathematics
1 answer:
Vilka [71]3 years ago
8 0

Answer:157

Step-by-step explanation:

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(12a + 8) + (4a + 3) + (5 + a) =
PSYCHO15rus [73]

Answer:

17a + 16 =

Step-by-step explanation:

Add all a's

then all numbers w/o letters

you cannot add them together bc it would be like adding apples to carrots (thats what my teacher said)

3 0
3 years ago
A class votes for their class President Kennedy receives 21 votes which is 6% of the vote what is the total number of students w
Katarina [22]

Answer:

21

Step-by-step explanation:

literally says it in the text ight

6 0
3 years ago
Read 2 more answers
Find the mean, median, and mode of the following set of data:
ddd [48]

Answer:

Step-by-step explanation:

mode is means the data which is repeated maximum number of times.

here 54 is repeated maximum number of times so the mode of the given data is 54.

to calculate median u must arrange the data from ascending to descending order.

37 , 42 , 48 , 51 , 52 , 53 , 54 , 54 , 55 ,

median = (N + 1) /2    (N means number of data)

=9 + 1/2

=10/2

=5 th term

=52

7 0
3 years ago
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Maria and Jamal each have gardens. The area of Maria’s garden is represented by the expression 8x2 – 3x. Jamal’s garden is a rec
mafiozo [28]

Answer:

sorry i do not know the answer you are looking for

Step-by-step explanation:

sorry the answer you are looking for cannot be found good luck though

3 0
4 years ago
How do I verify the identity: sec(t)+1/tan(t)=tan(t)/sec(t)-1
kompoz [17]
\bf \textit{Pythagorean Identities}
\\ \quad \\
sin^2(\theta)+cos^2(\theta)=1
\\ \quad \\
1+cot^2(\theta)=csc^2(\theta)
\\ \quad \\
\boxed{1+tan^2(\theta)=sec^2(\theta)}\implies tan^2(\theta)=sec^2(\theta)-1\\\\
-----------------------------\\\\
\cfrac{sec(x)+1}{tan(x)}=\cfrac{tan(x)}{sec(x)-1}\\\\
-----------------------------\\\\

\bf \cfrac{sec(x)+1}{tan(x)}\cdot \cfrac{sec(x)-1}{sec(x)-1}\impliedby \textit{using the conjugate}\\\\
-----------------------------\\\\
recall\qquad \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-----------------------------\\\\
thus\qquad \cfrac{sec^2(x)-1^2}{tan(x)sec(x)-1}\implies \cfrac{sec^2(x)-1}{tan(x)sec(x)-1}
\\\\\\
\cfrac{\underline{tan^2(x)}}{\underline{tan(x)} sec(x)-1}\implies \cfrac{tan(x)}{sec(x)-1}
4 0
4 years ago
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