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3 years ago

Justify the need for a control in an experiment. Use complete sentences

1 answer:

4 0

The control is necessary to make sure that you can tell the difference between the regular, non changed experiment, and the change that happens.
Basically, the control helps you to measure, or observe, the difference in experiments.

And example would be using pills, or flavor water, to see how it affects people.
The control would be the group that either doesn't receive pills or water. This is basically to see how it is normally. The norm.

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If a chemical has a pH of 3, how could you alter its pH value to be more basic?

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4 years ago

Calculate the volume of mercury with a density of 14.6 g/mL and a mass of 1.00 g. Please include a numeric value only with signi

Ne4ueva [31]

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4 years ago

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professor190 [17]

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3 years ago

Will mark the brainiest later for correct answers! Please show work.

Elodia [21]

Answer:

According to avogadro's law, 1 mole of every substance contains avogadro's number $6.023\times 10^{23}$ of particles and weighs equal to its molecular mass.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadros number}}$

a. moles in 14.08 g of $C_{12}H_{22}O_{11}$ = $\frac{14.08g}{342.3g/mol}=0.04113moles$

molecules in 14.08 g of $C_{12}H_{22}O_{11}$ = $0.04113\times 6.023\times 10^{23}=0.2477\times 10^{23}$

b. moles in 17.75 g of NaCl = $\frac{17.75g}{58.5g/mol}=0.3034moles$

molecules in 17.75 g of $NaCl$ = $0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}$

formula units 17.75 g of $NaCl$ = $0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}$

c. moles in 20.06 g of $CuSO_4.5H_2O$ = $\frac{20.06g}{249.68g/mol}=0.08034moles$

formula units in 20.06 g of $CuSO_4.5H_2O$ = $0.08034\times 6.023\times 10^{23}=0.4839\times 10^{23}$

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3 years ago

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iragen [17]

Answer:

1645.86

Explanation:

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3 years ago