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2 years ago

Question 7 of 18

Mathematics

1 answer:

Delicious77 [7]2 years ago

3 0

The more appropriate measures of center and spread are:

A. Better measure of spread: the interquartile range (IQR)
B. Better measure of center: the median

<h3>Which measures are best for the given data?</h3>

The better measure of the middle would be the median because mean is affected by low and high values which are present in the given data set.

As mean is not being used, standard deviation should not be used for the same reason. This leaves us with the interquartile range which is best because it does not take outliers into account.

Find out more on the Interquartile Range at brainly.com/question/12568713.

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There are 32 students in a class how many ways can the Class be divided into groups with equal numbers of students are what are

kumpel [21]

They can be divided into

2 groups of 16
4 groups of 8
8 groups of 4
16 groups of 2

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3 years ago

Persons having Raynaud's syndrome are apt to suffer a sudden impairment of blood circulation in fingers and toes. In an experime

Citrus2011 [14]

Answer:

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

Step-by-step explanation:

We have to perform a hypothesis test on the difference between means.

The null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a: \mu_1-\mu_2$

μ1: mean heat output for subjects with the syndrome.

μ2: mean heat output for non-sufferers.

We will use a significance level of 0.05.

The difference between sample means is:

$M_d=\bar x_1-\bar x_2=0.63-2.09=-1.46$

The standard error is

$s_{M_d}=\sqrt{\sigma_1^2/n_1+\sigma_2^2/n_2}=\sqrt{0.3^2/9+0.5^2/9}=\sqrt{ 0.038 } \\\\ s_{M_d}=0.194$

The t-statistic is

$t=\dfrac{M_d}{s_{M_d}}=\dfrac{-1.46}{0.194}=-7.52$

The degrees of freedom are

$df=n_1+n_2-2=9+9-2=16$

The critical value for a left tailed test at a significance level of 0.05 and 16 degrees of freedom is t=-1.746.

The t-statistic is below the critical value, so it lies in the rejection region.

The null hypothesis is rejected.

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

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3 years ago

Ms. Carr's Class Is Selling Magazines To Raise Money For A Field Trip. The Students In The Class Device They Wanted To Make 5.50

FinnZ [79.3K]

Here you are giving only the amount they want to raise (namely profit times number of magazines sold), and here you are also giving Money they want to raise... So clarifying, the money they want to raise, should include the money they will spend on buying the magazines (there is no statement saying they found them, or were given the magazines, so a cost should be involved)

Now if they are only making the count of "Field trip costs X amount of money, and given we have to make a profit of $5.5, How many must we sell?" then the equation should be n=X/5.5

Should the story be, how much money must they raise to have a profit of 5.5 on each magazine and still have enough for the field trip, then you have a different equation which varies only in adding the cost of each magazine, either case, M should be defined not as money they need to raise (cause here they will be short on their goal) but Money they must earn. And again, you should rewrite your equation to be:

M=Amount they must raise
C=Cost per magazine
n=Number of magazines
p=profit $5.5 per magazine

C+p=M/n

And rewriting the previous they should make:

n(C+p)=M -----> n(C+5.5)=M <span>m/n = 5.50 </span>
<span>m/n x n = 5.50 x n //// multiply each side by n </span>

<span>m = 5.5n</span>

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3 years ago

Read 2 more answers

Condense the expression log 2x + log(x² - 9) - log x +3

Rudik [331]

Here the my solutions,hope you understand