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2 years ago

Question 7 of 18

Mathematics

1 answer:

Delicious77 [7]2 years ago

3 0

The more appropriate measures of center and spread are:

A. Better measure of spread: the interquartile range (IQR)
B. Better measure of center: the median

<h3>Which measures are best for the given data?</h3>

The better measure of the middle would be the median because mean is affected by low and high values which are present in the given data set.

As mean is not being used, standard deviation should not be used for the same reason. This leaves us with the interquartile range which is best because it does not take outliers into account.

Find out more on the Interquartile Range at brainly.com/question/12568713.

#SPJ1

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Whichwhich would you measure using inches? A. length of a pen B. height of a flagpole C. length of a cross-country race course D

Taya2010 [7]

Answer:

The length of a pen.

Step-by-step explanation:

A length of a pen is around three inches and is reasonable but all of the others are way too big and can be measured in feet or miles.

3 0

3 years ago

A class of 33 students elected a class treasurer. there were 111votes for candidate a and 15 votes for candidate

Advocard [28]

Since 111 is greater than 33, I will assume that you meant 11 votes for a candidate. Also, assuming that each student can vote only once, the answer would be

11/33 x 100=33.333333...

About 33.333 of the voters voted for candidate a.

3 0

3 years ago

In a line of students ,Jenna is number 8.The teacher says the rule for a number pattern is add4.The first term 7.What number sho

balandron [24]

1. You have that the rule for a number pattern is add 4 and the first term is 7.

2. Let's call "n" to the number in the line where each student is. Then, you can express this as below:

4n+7

3. So, you have:

Student N°1=4(1)+7=11
 Student N°2=4(2)+7=15
Student N°3=4(3)+7=19
Student N°4=4(4)+7=23
Student N°5=4(5)+7=27
Student N°6=4(6)+7=31
Student N°7=4(7)+7=35
Student N°8=4(8)+7=39

What number should Jenna say?

The answer is: 39

4 0

3 years ago

in triunghiul isoscel ABC, AB=AC=36cm, m(BAC)=45°, iar BE perpendicular pe AC, E apartine (AC). Calculati Aria ABC, BE

melisa1 [442]

when given SAS, the area (A) of the triangle = (side1 · sin θ · side2)/2

A = (36 · sin 45° · 36)/2

= (36² · √2)/4

= 9 · 36 · √2

= 324√2

≈ 458.2

4 0

3 years ago

Question 6 (1.25 points)

Lisa [10]

Answer:

Test statistic Z= 1.713

The calculated Z- value = 1.7130 < 2.576 at 0.01 level of significance

Null hypothesis is accepted

There is no difference between the mean annual salary of all lawyers in a city is different from $110,000

Step-by-step explanation:

Step(i):-

A researcher wants to test if the mean annual salary of all lawyers in a city is

different from $110,000

Mean of the Population μ = $110,000

Sample size 'n' = 53

Mean of the sample x⁻ = $114,000.

standard deviation of the Population = $17,000,

Level of significance = 0.01

Null hypothesis :

There is no difference between the mean annual salary of all lawyers in a city is different from $110,000

H₀: x⁻ = μ

Alternative Hypothesis : x⁻ ≠ μ

Step(ii):-

Test statistic

$Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }$

$Z = \frac{114000-110000}{\frac{17000}{\sqrt{53} } }$

Z = 1.7130

Tabulated value Z = 2.576 at 0.01 level of significance

The calculated Z- value = 1.7130 < 2.576 at 0.01 level of significance

Null hypothesis is accepted

There is no difference between the mean annual salary of all lawyers in a city is different from $110,000

4 0

3 years ago