Answer:
To be inspected line by line.
Explanation:
Answer:
#include <iostream>
using namespace std;
int main() {
int a[4][5];//declaring a matrix of 4 rows and 5 columns.
for(int i=0;i<4;i++)
{
for(int j=0;j<5;j++)
{
if(i==3)//initializing last row as 0.
{
a[i][j]=0;
}
else//initializing last row as 1.
{
a[i][j]=1;
}
}
}
for(int i=0;i<4;i++)
{
for(int j=0;j<5;j++)
cout<<a[i][j]<<" ";//printing the matrix.
cout<<endl;
}
return 0;
}
Output:-
1 1 1 1 1
1 1 1 1 1
1 1 1 1 1
0 0 0 0 0
Explanation:
I have created a matrix of size 4 rows and 5 columns.I have used for loops to fill the array.To fill the last row with 0 i have used if statement.else we are filling it with 1.
Answer:
<em>#include <iostream></em>
<em>using namespace std;</em>
<em>int main()</em>
<em>{</em>
<em> int myNewAge;</em>
<em> int myCurrentAge = 29;</em>
<em> int currentYear = 2020;</em>
<em> </em>
<em>myNewAge = myCurrentAge+(2050-currentYear);</em>
<em />
<em>cout<<"My Current Age is "<<myCurrentAge<<". I will be "<<myNewAge<<" in 2050"<<endl;</em>
<em> return 0;</em>
<em>}</em>
Explanation:
The program is written in C++ language as required. firstly, we declare the three variables:
<em> </em><em>int myNewAge;</em>
<em> int myCurrentAge = 29;</em>
<em> int currentYear = 2020;</em>
Then we calculate the new age as: <em>myNewAge = myCurrentAge+(2050-currentYear);</em>
Using multiple cout operators (<em> </em><<) we display the output nicely as required by the question with this statement
<em>cout<<"My Current Age is "<<myCurrentAge<<". I will be "<<myNewAge<<" in 2050"<<endl;</em>
