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taurus [48]
2 years ago
8

Please help me do the equation and figure out the right solution. I am supposed to be correcting the one in the picture.

Mathematics
1 answer:
alexira [117]2 years ago
5 0

Answer:

The correct answer is if you want no roots in the denominator, the correct answer is \frac{2x}{y}* \sqrt[3]{2y^{2} }

Step-by-step explanation:

The mistake is that you can't take a cube root of a square at step 3 when y^{2} is taken out.

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torisob [31]

Answer:

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What is the opposite of (-6v + 1)?
jarptica [38.1K]
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8 0
3 years ago
1.
mr_godi [17]
Plug the points into the equation.
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