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DiKsa [7]
2 years ago
11

VERY URGENT GIVING BRAINLY​

Physics
1 answer:
lakkis [162]2 years ago
8 0

Answer:

A

Explanation:

There is a mechanical advantage in this system....

    she only needed 100 N to lift 500 N

        1:5      she lifted it 2 meters, so if there WAS NO friction, she would have to pull in 5 x 2 = 10 meters

   but there IS friction so she must have pulled in MORE than 10 m  

You might be interested in
An 5-kg animal accelerates from rest to 10 m/s in 10 m and encounters an average drag force of 12 N. What is the average power o
MArishka [77]

Answer:

60 watts

Explanation:

Given that

Mass of the animal, m = 5 kg

Velocity of the animal, v = 10 m/s

Distance moved by the animal, d = 10 m

Drag force, F(d) = 12 N

Time taken, t = 2 seconds

To start with, we need to find the power output in itself before proceeding to find the average power output. And as such, we have

Power = Force * Distance/Time

But Distance/Time is velocity, so

Power = Force * Velocity

Power = 12 * 10

Power = 120 W.

We then use this power gotten to find the average power output.

Power(avg) = P/t

Power(avg) = 120 / 2

Power(avg) = 60 Watts.

Therefore, the average power output is found to be 60 Watts

5 0
4 years ago
Fill in the blanks:
oksano4ka [1.4K]
<h2>Answers:</h2>

<h2>1. event horizon </h2>

The event horizon is the surface of a black hole, it is the border of space-time in which the events on one side of it can not affect an observer on the other side.

That is, at this border also called <em>"point of no return"</em>, nothing can escape (not even light) and no event that occurs within it can be seen from outside.  

<h2>2. gravitational lensing  </h2>

According to Einstein's theory of relativity, mass causes the curvature of spacetime and this curvature is what we call <u>gravity</u>.

Then, the light always move following the curvature that gravity causes in spacetime, and in this way the rays of light are deflected if there is a mass accumulation nearby. Being this is the principle of the gravitational lensing.

<h2>3. black hole </h2>

According to Einstein's theory of relativity, inside a black hole there is a <em>"singularity"</em> that consists of a region of the space in which <u>the density of matter tends to infinity. </u>

How is it possible?

Following what relativity establishes, bodies within a gravitational field follow a curved space path. Then the more a body enters the black hole, the more curved the space will become, until, in the center, it will become infinitely curved.

<h2>4. gravitational waves </h2>

Gravitational waves were discovered (theoretically) by Albert Einstein in 1916 and "observed" for the first time in direct form in 2015.

These gravitational waves  are fluctuations or disturbances of space-time produced by a massive accelerated body, modifying the distances and the dimensions of objects in an imperceptible way.

In this context, an excellent example is the system of two neutron stars that orbit high speeds, producing a deformation that propagates like a wave, <u>in the same way as when a stone is thrown into the water. </u>

<h2>5. wormhole</h2>

A wormhole is <u>a hypothetical feature of a space-time</u> described in the equations of general relativity, which essentially consists of a shortcut through space and time.  It is not proven that they exist, although <u>mathematically they are possible</u> .

In other words:

A wormhole is a tunnel that joins two black holes in different places (two points of spacetime).

<h2>6. time dilation (gravitational) </h2>

The dilation of time is a phenomenon that results from the theory of relativity, which states that time passes at different rates in regions of different gravitational potential.

That is, the greater the local distortion of spacetime due to gravity, the slower the time passes.

<h2>7.  gravitational redshift</h2><h2 />

When we talk about the <u>visible electromagnetic spectrum</u>, we know it starts in violet-blue and ends in red.  

Now, in this context the astronomer Edwin Powell Hubble observed several celestial bodies, and when obtaining the spectra of distant galaxies he observed that the spectral lines were displaced towards the red one (red shift), whereas the nearby stars showed a spectrum displaced to the blue one.  

From there, it was deduced that the farther an body in the universe is, the more redshifted it is in its spectrum.  This effect is due to the dilation and contraction of time by speed.  

7 0
3 years ago
A 4 kg particle moves at a constant speed of 2.5 m/s around acircle of radius 2 m. What is its angular momentum about the center
blagie [28]

Explanation:

Given that,

Mass of the particle, m = 4 kg

Speed of the particle, v = 2.5 m/s

The radius of the circle, r = 2 m

We need to find the angular momentum about the center of the circle. The formula for the angular momentum is given by :

L=mvr

Substitute all the values,

L=4\times 2.5\times 2\\\\L=20\ kg{\cdot}m^2s

So, the angular momentum of the particle is 20 kg-m² s.

6 0
3 years ago
A 426.7 Hz tuning fork is resonating in a closed tube on a warm day when the speed of sound is 346 m/s.
Grace [21]

Answer:0.8 meter

Explanation:

Frequency=426.7hz

Velocity=346m/s

Length =velocity ➗ frequency

Length=346 ➗ 426.7

Length =0.8

8 0
3 years ago
The flagpole is held vertical by two ropes. The first of these ropes has a tension in it of 100 N and is at an angle of 60° to t
KatRina [158]

Answer:

T₂ = 123.9 N,  θ = 66.2º

Explanation:

To solve this exercise we use the law of equilibrium, since the diaphragm does not appear, let's use the adjoint to see the forces in the system.

The tension T1 = 100 N, we create a reference frame centered on the pole

X axis

       T₁ₓ - T_{2x} = 0

        T_{2x}= T₁ₓ

Y axis y

      T_{1y} + T_{2y} - 200N = 0

      T_{2y} = 200 -T_{1y}

let's use trigonometry to find the component of the stresses

         sin 60 = T_{1y} / T₁

         cos 60 = t₁ₓ / T₁

         T_{1y} = T₁ sin 60

         T1x = T₁ cos 60

         T_{1y}y = 100 sin 60 = 86.6 N

         T₁ₓ = 100 cos 60 = 50 N

for voltage 2 it is done in the same way

         T_{2y} = T₂ sin θ

         T₂ₓ = T₂ cos θ

we substitute

         

           T₂ sin θ= 200 - 86.6 = 113.4

           T₂ cos θ = 50              (1)

to solve the system we divide the two equations

           tan θ = 113.4 / 50

           θ = tan⁻¹ 2,268

           θ = 66.2º

we caption in equation 1

           T₂ cos 66.2 = 50

           T₂ = 50 / cos 66.2

           T₂ = 123.9 N

8 0
3 years ago
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