Answer:
The electric potential of the uniformly charge disk is 1392.1 V
Explanation:
Electric potential, for a uniformly charged disk at a distance A, is given as;
![V = \frac{\sigma}{2 \epsilon} [\sqrt{A^2 +R^2} -A]](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B%5Csigma%7D%7B2%20%5Cepsilon%7D%20%5B%5Csqrt%7BA%5E2%20%2BR%5E2%7D%20-A%5D)
Where;
σ is the charge density = 1.40 μC/m³
ε is the permittivity of free space = 8.85 x 10⁻¹²
A is the distance above the disk = 40 cm = 0.4 m
R is the radius of the disk = 0.12 m
Substitute in these values into the equation above, we will have
![V = \frac{1.4 X 10^{-6}}{2X8,85X10^{-12}}[\sqrt{0.4^2 +0.12^2}-0.4] \\\\V = (79096.05)(0.0176) = 1392.1 V](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B1.4%20X%2010%5E%7B-6%7D%7D%7B2X8%2C85X10%5E%7B-12%7D%7D%5B%5Csqrt%7B0.4%5E2%20%2B0.12%5E2%7D-0.4%5D%20%5C%5C%5C%5CV%20%3D%20%2879096.05%29%280.0176%29%20%3D%201392.1%20V)
Therefore, the electric potential of the uniformly charge disk is 1392.1 V
Explanation:
it is given that, the linear charge density of a charge, 
Firstly, we can define the electric field for a small element and then integrate for the whole. The very small electric field is given by :
..........(1)
The linear charge density is given by :


Integrating equation (1) from x = x₀ to x = infinity



Hence, this is the required solution.
Answer:
A. Potassium
B. Potassium
C. Bromine
D. Bromine and Krypton potassium
E. Barium
F. Arsenic and Geranium
G.
Explanation:
Answer:
please find attached file
Explanation:
When oxygen reacts with magnesium thenMgO3 is formed.
Mg +O2----> MgO3