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seraphim [82]
3 years ago
15

Fill in the blanks:

Physics
1 answer:
oksano4ka [1.4K]3 years ago
7 0
<h2>Answers:</h2>

<h2>1. event horizon </h2>

The event horizon is the surface of a black hole, it is the border of space-time in which the events on one side of it can not affect an observer on the other side.

That is, at this border also called <em>"point of no return"</em>, nothing can escape (not even light) and no event that occurs within it can be seen from outside.  

<h2>2. gravitational lensing  </h2>

According to Einstein's theory of relativity, mass causes the curvature of spacetime and this curvature is what we call <u>gravity</u>.

Then, the light always move following the curvature that gravity causes in spacetime, and in this way the rays of light are deflected if there is a mass accumulation nearby. Being this is the principle of the gravitational lensing.

<h2>3. black hole </h2>

According to Einstein's theory of relativity, inside a black hole there is a <em>"singularity"</em> that consists of a region of the space in which <u>the density of matter tends to infinity. </u>

How is it possible?

Following what relativity establishes, bodies within a gravitational field follow a curved space path. Then the more a body enters the black hole, the more curved the space will become, until, in the center, it will become infinitely curved.

<h2>4. gravitational waves </h2>

Gravitational waves were discovered (theoretically) by Albert Einstein in 1916 and "observed" for the first time in direct form in 2015.

These gravitational waves  are fluctuations or disturbances of space-time produced by a massive accelerated body, modifying the distances and the dimensions of objects in an imperceptible way.

In this context, an excellent example is the system of two neutron stars that orbit high speeds, producing a deformation that propagates like a wave, <u>in the same way as when a stone is thrown into the water. </u>

<h2>5. wormhole</h2>

A wormhole is <u>a hypothetical feature of a space-time</u> described in the equations of general relativity, which essentially consists of a shortcut through space and time.  It is not proven that they exist, although <u>mathematically they are possible</u> .

In other words:

A wormhole is a tunnel that joins two black holes in different places (two points of spacetime).

<h2>6. time dilation (gravitational) </h2>

The dilation of time is a phenomenon that results from the theory of relativity, which states that time passes at different rates in regions of different gravitational potential.

That is, the greater the local distortion of spacetime due to gravity, the slower the time passes.

<h2>7.  gravitational redshift</h2><h2 />

When we talk about the <u>visible electromagnetic spectrum</u>, we know it starts in violet-blue and ends in red.  

Now, in this context the astronomer Edwin Powell Hubble observed several celestial bodies, and when obtaining the spectra of distant galaxies he observed that the spectral lines were displaced towards the red one (red shift), whereas the nearby stars showed a spectrum displaced to the blue one.  

From there, it was deduced that the farther an body in the universe is, the more redshifted it is in its spectrum.  This effect is due to the dilation and contraction of time by speed.  

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Sketch the path that light would take through the slit. Show the beams that are incident on and reflected from the mirror. Draw
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by superposition method we can find current in R5

here first let say only 2V battery is present in the circuit

now the equivalent resistance to be found for which we can say

2.2 k ohm and 1 k ohm is connected in parallel

r_1 = \frac{2.2 * 1}{2.2 + 1}

r_1 = 0.6875 k ohm

now it is in series with 1 k ohm and then that part is in parallel with 2.2 k ohm

r_2 = \frac{2.2* (1+0.6875)}{2.2 + (1+0.6875)}

r_2 = 0.95 k ohm

now the current flowing through the battery is

i = \frac{2}{1 + 0.95} = 1.02 mA

now this will divide into R3 and R2 so current flowing in R3 will be

i_1 = \frac{2.2}{2.2+1.6875}*1.02 = 0.58 mA

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also after its series with R3

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now it is in parallel with R5 on other side

r_3 = \frac{1.6875 * 2.2}{1.6875 + 2.2} = 0.95 k ohm

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now it is divide in r2 and R5

so current in R5 is given as

i_5 = \frac{r_2}{r_2 + R_5}*i

i_5 = \frac{1.6875}{2.2 + 1.6875} * 1.53

i_5 = 0.67 mA

now the total current in R5 will be given by super position which is

i = 0.67 + 0.18 = 0.85 mA

so there is 0.85 mA current through R5 resistance

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