1.- La gráfica muestra la variación de la aceleración a de un objeto con el tiempo t.

"A bridge, constructed of 11 beams of equal length L and negligible mass, supports an object of mass M.

fiasKO [112]

F_P + F_Q = M g
F_P = M g - F_Q
Torque, or moment of force:
∑ M_P = 0
∑ M_P = M g L - F_Q · 3 L
0 = M g L - 3 F_Q L / : L
0 = M g - 3 F_Q
3 F_Q = M g
F_Q = M g /3
Finally:
F_P = M g - M g/3
F_P = 4 M g / 3

7 0

3 years ago

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Q.1. What determines the rate at which energy is delivered by a current ?

aksik [14]

Explanation:

The rate of consumption of electric energy in an electric appliance is called electric power. Hence, the rate at which energy is delivered by a current is the power of the appliance.

8 0

3 years ago

Carbon dioxide enters an adiabatic nozzle steadily at 1 MPa, 518 oC, and mass flow rate of 5,322 kg/h and exits the system at 96

Orlov [11]

Answer:

The velocity at the nozzle at inlet $V_{1}$ = 3584 $\frac{m}{sec}$

Explanation:

Pressure at inlet $P_{1}$ = 1 × $10^{6}$ Pa

Temperature at inlet $T_{1}$ = 518 ° c = 791 K

Mass flow rate = $\frac{5322}{60}$ $\frac{kg}{sec}$ = 88.7

Gas constant for carbon die oxide is R = 189 $\frac{J}{kg k}$

Mass flow rate inside the nozzle is given by the formula = $\frac{P_{1} }{R T_{1} }$ × $A_{1}$ × $V_{1}$

⇒ $P_{1}$ = = 1 × $10^{6}$ Pa

⇒ R $T_{1}$ = 791 × 189 = 149499 $\frac{J}{kg}$

⇒ $A_{1}$ = 0.0037 $m^{2}$

Put all the above values in above formula we get,

⇒ 88.7 = $\frac{10^{6} }{149499}$ × 0.0037 × $V_{1}$

⇒ $V_{1}$ = 3584 $\frac{m}{sec}$

This is the velocity at the nozzle at inlet.

3 0

3 years ago

Why is gravity important in the solar system

Orlov [11]

Gravity causes the motions of planets, stars, and galaxies. It's why the Moon orbits around the Earth, and the Earth orbits around the Sun, and the solar system orbits around the galaxy.

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3 years ago

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You have three objects of varying shapes and sizes: Object 1 is a rectangular block of tin. Object 2 is a cube of aluminum. Obje

Over [174]

Answer: a. m = 7.7 kg

b. V = 435.52 in³

c. m = 1927 kg

d. V = 335.37 cm³

e. m = 3 kg

Explanation: <u>Density</u> is the ratio of mass per volume, i.e., it's the measure of an object's compactness. Its representation is the greek letter ρ.

The formula for density is

$\rho=\frac{m}{V}$

Density's unit in SI is kg/m³, but it can assume lots of other units.

Some unit transformations necessary for the resolution of the question:

1 L = 1 dm³ = 1000 cm³

1 in³ = 16.3871 cm³

1 g = 0.001 kg

a. V = 1.34 L = 1340 cm³

$\rho=\frac{m}{V}$

$m=\rho.V$

m = 5.75 * 1340

m = 7705 g => 7.705 kg

Mass of object 1 with volume 1.34L is 7.7 kg.

b. A cube's volume is calculated as V = side³

V = 7.58³

V = 435.52 in³

Volume of object 2 is 435.52 in³.

c. Using 1 in³ = 16.3871 cm³ to change units:

V = 435.52 * 16.3871

V = 713689.4 cm³

Then, mass will be

$m=\rho.V$

m = 2.7 * 713689.4

m = 1926961.4 g => 1927 kg

Mass of object 2 is 1927 kg.

d. Volume of a sphere is calculated as $V=\frac{4}{3}.\pi.r^{3}$

Diameter is twice the radius, then r = 4.31 cm.

Volume is

$V=\frac{4}{3}.\pi.(4.31)^{3}$

V = 335.37 cm³

Volume of object 3 is 335.37 cm³.

e. $m=\rho.V$

m = 8.96 * 335.37

m = 3004.91 g => 3 kg

Mass of object 3 is 3 kg.

4 0

3 years ago