A 4 kg particle moves at a constant speed of 2.5 m/s around acircle of radius 2 m. What is its angular momentum about the center
1 answer:
Explanation:
Given that,
Mass of the particle, m = 4 kg
Speed of the particle, v = 2.5 m/s
The radius of the circle, r = 2 m
We need to find the angular momentum about the center of the circle. The formula for the angular momentum is given by :
Substitute all the values,
So, the angular momentum of the particle is 20 kg-m² s.
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Answer:
Explanation:
Given that,
Initially, the spaceship was at rest, u = 0
Final velocity of the spaceship, v = 11 m/s
Distance accelerated by the spaceship, d = 213 m
We need to find the acceleration experienced by the occupants of the spaceship during the launch. It is a concept based on the equation of kinematics. Using the third equation of motion to find acceleration.
So, the acceleration experienced by the occupants of the spaceship is .
Answer:
Angular acceleration is defined as the rate of change of angular velocity of a body.
consider the attached figure as shown
It rotates with an angular velocity
An point inside the object rotates along the path as indicated thus turning by an angle in time 't'
Thus we have
physically angular acceleration can be understood as the rate at which the angular speed of any object is changing with time.
Answer: 4.5 V
Explanation:
Given
The voltage of each cell is 1.5 V
If they are connected end to end their potential added to give a higher potential i.e. 1.5+1.5+1.5=4.5 V
