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Charra [1.4K]
3 years ago
5

Help please!!

Mathematics
1 answer:
Pavel [41]3 years ago
5 0

Answer:

1. Left side = 3 inches, Bottom side = 4 inches, Right side = 2 inches, Top side = 5 inches

2.  A = 6 inches²

3.  A = 8 inches²

4.  A = 10 inches²

5.  A = 12 inches²

6.  A = 36 inches²

7. Left side = 5 cm, Bottom side = 12 cm, Right side = 4 cm, Top side = 13 cm

8. A = 180 cm²

Step-by-step explanation:

1. Label the dimensions of the prism:

Left side = 3 inches

Bottom side = 4 inches

Right side = 2 inches

Top side = 5 inches

2. Area of the red rectangle:

Formula:

LH = A (Length x Height = Area)

A = 3 x 2

A = 6 inches²

3. Area of the blue rectangle:

Formula:

LH = A (Length x Height = Area)

A = 4 x 2

A = 8 inches²

4. Area of the green rectangle:

Formula:

LH = A (Length x Height = Area)

A = 5 x 2

A = 10 inches²

5. (They gave the formula of the two triangles, but the question said green rectangle?  They must've meant yellow triangles)

Area of the yellow triangles:

Formula:

2 (1/2 Bh) (2 (half of base x height))

A = 2(1/2 3 x 4)

A = 2(1/2 12)

A = 2(6)

A = 12 inches²

6. Total surface area of the triangular prism:

Formula:

LH + LH + LH + 2 (1/2 Bh) = Surface Area of the triangular prism (Area of the red rectangle + Area of the blue rectangle + Area of the green rectangle + Area of the yellow triangles = Total surface area of the triangular prism)

A = 6 inches² + 8 inches² + 10 inches² + 12 inches²

A = 36 inches²

7. Label the dimensions of the prism:

Left side = 5 cm

Bottom side = 12 cm

Right side = 4 cm

Top side = 13 cm

8. Total surface area of the triangular prism:

First, we can find the area of each shape, as we had previously to find the total area of the net and the surface area of the triangular prism.

Area of the red rectangle:

Formula:

LH = A (Length x Height = Area)

A = 5 x 4

A = 20 cm²

Area of the blue rectangle:

Formula:

LH = A (Length x Height = Area)

A = 12 x 4

A = 48 cm²

Area of the green rectangle:

Formula:

LH = A (Length x Height = Area)

A = 13 x 4

A = 52 cm²

Area of the yellow triangles:

Formula:

2 (1/2 Bh) (2 (half of base x height))

A = 2(1/2 5 x 12)

A = 2(1/2 60)

A = 2(30)

A = 60 cm²

Total surface area of the triangular prism:

LH + LH + LH + 2 (1/2 Bh) = Surface Area of the triangular prism (Area of the red rectangle + Area of the blue rectangle + Area of the green rectangle + Area of the yellow triangles = Total surface area of the triangular prism)

A = 20 cm² + 48 cm² + 52 cm² + 60 cm²

A = 180 cm²

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Answer:

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24-20=y

4=y

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Talia tossed a penny many times. She got 20 heads and 80 tails. She said the experimental probability of getting heads was 20 80
iragen [17]

Answer:

the experimental probability is 1/5

Step-by-step explanation:

This is because one to calculate the experimental probability one has to divide the favorable events over the possible events, and those that Talia did were the favorable events divided the non-favorable events

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Faborable events = 20

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5 0
3 years ago
The Center for Medicare and Medical Services reported that there were 295,000 appeals for hospitalization and other Part A Medic
Ymorist [56]

Answer:

(a) 0.00605

(b) 0.0403

(c) 0.9536

(d) 0.98809

Step-by-step explanation:

We are given that 40% of first-round appeals were successful (The Wall Street Journal, October 22, 2012) and suppose ten first-round appeals have just been received by a Medicare appeals office.

This situation can be represented through Binomial distribution as;

P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....

where,  n = number of trials (samples) taken = 10

            r = number of success

            p = probability of success which in our question is % of first-round

                   appeals that were successful, i.e.; 40%

So, here X ~ Binom(n=10,p=0.40)

(a) Probability that none of the appeals will be successful = P(X = 0)

     P(X = 0) = \binom{10}{0}0.40^{0}(1-0.40)^{10-0}

                   = 1*0.6^{10} = 0.00605

(b) Probability that exactly one of the appeals will be successful = P(X = 1)

     P(X = 1) = \binom{10}{1}0.40^{1}(1-0.40)^{10-1}

                  = 10*0.4^{1} *0.6^{10-1} = 0.0403

(c) Probability that at least two of the appeals will be successful = P(X>=2)

    P(X >= 2) = 1 - P(X = 0) - P(X = 1)

                     = 1 - \binom{10}{0}0.40^{0}(1-0.40)^{10-0} - \binom{10}{1}0.40^{1}(1-0.40)^{10-1}

                     = 1 - 0.00605 - 0.0403 = 0.9536

(d) Probability that more than half of the appeals will be successful =             P(X > 0.5)

  For this probability we will convert our distribution into normal such that;

   X ~ N(\mu = n*p=4,\sigma^{2}= n*p*q = 2.4)

  and standard normal z has distribution as;

      Z = \frac{X-\mu}{\sigma} ~ N(0,1)

  P(X > 0.5) = P( \frac{X-\mu}{\sigma} > \frac{0.5-4}{\sqrt{2.4} } ) = P(Z > -2.26) = P(Z < 2.26) = 0.98809

3 0
3 years ago
I need help with this problem
meriva
I'm sorry, I don't see the question. Could you please retake the photo in better quality so I could answer it? Thanks!
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4 years ago
Factorise<br>x2 + 2x - 3​
Nitella [24]

Answer:

( x − 1 ) ( x +3 )

8 0
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